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tiny-mole [99]
3 years ago
6

What would the solution of y=-x+2 and x-4y=-28

Mathematics
1 answer:
malfutka [58]3 years ago
4 0

Answer:

x = -4

Step-by-step explanation:

If y is equal to-x + 2 then you can plug that into the second equation as x - 4(-x + 2) = -28 after this distribute out the -4 to get x + 4x - 8 = -28. After this combine the like terms to get 5x = -20. Then get x by itself by dividing by 5 to get x = -4.

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4 0
3 years ago
A set of equations is given below:
Hunter-Best [27]
If you would like to find a step that can be used to find the solution to the set of equations, you can do this using the following steps:

c = 2d + 1
c = 3d + 5
__________
c = c
2d + 1 = 3d + 5
2d - 3d = 5 - 1
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d = -4

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8 0
3 years ago
16 POINTS
Marta_Voda [28]
Solve the following system using elimination:
{7 x + 2 y = -19 | (equation 1)
{2 y - x = 21 | (equation 2)

Add 1/7 × (equation 1) to equation 2:
{7 x + 2 y = -19 | (equation 1)
{0 x+(16 y)/7 = 128/7 | (equation 2)

Multiply equation 2 by 7/16:
{7 x + 2 y = -19 | (equation 1)
{0 x+y = 8 | (equation 2)

Subtract 2 × (equation 2) from equation 1:
{7 x+0 y = -35 | (equation 1)
{0 x+y = 8 | (equation 2)

Divide equation 1 by 7:
{x+0 y = -5 | (equation 1)
{0 x+y = 8 | (equation 2)

Collect results:
Answer: {x = -5, y = 8
8 0
3 years ago
Find all the square roots of x2 ≡ 53 (mod 77)
Nikolay [14]

Answer:

x=\pm\sqrt{77n+53}

Step-by-step explanation:

We have been given an equivalence equation x^2\equiv 53\text{ (mod } 77). We are asked to find all the square root of the given equivalence equation.

Upon converting our given equivalence equation into an equation, we will get:

x^2-53=77n

Add 53 on both sides:

x^2-53+53=77n+53

x^2=77n+53

Take square root of both sides:

x=\pm\sqrt{77n+53}

Therefore, the square root for our given equation would be x=\pm\sqrt{77n+53}.

3 0
3 years ago
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