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4 years ago

3(6x - 4) X 24x = 18(3x + 4) - 4

Mathematics

1 answer:

stellarik [79]4 years ago

4 0

Answer:

$x = 0.95627194... and \: y = - 0.16460527$

Step-by-step explanation:

find a,b,c of the quadratic and then use the quadratic formula

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The diagram shows a triangle 60° 11y 4y What is the value of y? y =

Vedmedyk [2.9K]

Answer:

y = 8

Step-by-step explanation:

11y + 4y + 60 = 180

11y + 4y = 120

15y = 120

y = 8

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3 years ago

A playground is on a rectangular pad that can be mulched. The park service just bought a load of mulch and they bought 60 square

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The width of the rectangular pad is 7.5 feet.

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3 years ago

For a certain river, suppose the drought length Y is the number of consecutive time intervals in which the water supply remains

AnnZ [28]

Answer:

a) There is a 9% probability that a drought lasts exactly 3 intervals.

There is an 85.5% probability that a drought lasts at most 3 intervals.

b)There is a 14.5% probability that the length of a drought exceeds its mean value by at least one standard deviation

Step-by-step explanation:

The geometric distribution is the number of failures expected before you get a success in a series of Bernoulli trials.

It has the following probability density formula:

$f(x) = (1-p)^{x}p$

In which p is the probability of a success.

The mean of the geometric distribution is given by the following formula:

$\mu = \frac{1-p}{p}$

The standard deviation of the geometric distribution is given by the following formula:

$\sigma = \sqrt{\frac{1-p}{p^{2}}$

In this problem, we have that:

$p = 0.383$

$\mu = \frac{1-p}{p} = \frac{1-0.383}{0.383} = 1.61$

$\sigma = \sqrt{\frac{1-p}{p^{2}}} = \sqrt{\frac{1-0.383}{(0.383)^{2}}} = 2.05$

(a) What is the probability that a drought lasts exactly 3 intervals?

This is $f(3)$

$f(x) = (1-p)^{x}p$

$f(3) = (1-0.383)^{3}*(0.383)$

$f(3) = 0.09$

There is a 9% probability that a drought lasts exactly 3 intervals.

At most 3 intervals?

This is $P = f(0) + f(1) + f(2) + f(3)$

$f(x) = (1-p)^{x}p$

$f(0) = (1-0.383)^{0}*(0.383) = 0.383$

$f(1) = (1-0.383)^{1}*(0.383) = 0.236$

$f(2) = (1-0.383)^{2}*(0.383) = 0.146$

Previously in this exercise, we found that $f(3) = 0.09$

$P = f(0) + f(1) + f(2) + f(3) = 0.383 + 0.236 + 0.146 + 0.09 = 0.855$

There is an 85.5% probability that a drought lasts at most 3 intervals.

(b) What is the probability that the length of a drought exceeds its mean value by at least one standard deviation?

This is $P(X \geq \mu+\sigma) = P(X \geq 1.61 + 2.05) = P(X \geq 3.66) = P(X \geq 4)$ .

We are working with discrete data, so 3.66 is rounded up to 4.

Either a drought lasts at least four months, or it lasts at most thee. In a), we found that the probability that it lasts at most 3 months is 0.855. The sum of these probabilities is decimal 1. So:

$P(X \leq 3) + P(X \geq 4) = 1$

$0.855 + P(X \geq 4) = 1$

$P(X \geq 4) = 0.145$

There is a 14.5% probability that the length of a drought exceeds its mean value by at least one standard deviation

8 0

4 years ago

Please help me with numbers 1 & 2. Please show work, thank you.

Orlov [11]

1.) Jarvis lives 3 miles away from Cassidy and Theo lives 6 miles away.
(if Jarvis lives 3 miles away from Cassidy and Theo is twice as far from Jarvis, Theo would be twice as many miles away from Cassidy than Jarvis; 3 times 2 is 6; 3+6+=9)
2.) Jorge's watering can can hold 8 cups of water.
(Older brother's can hold 16 cups; 8+8+16= 32; there are 32 cups in 2 gallons)

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4 years ago

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I need help with these two questions please!

Novay_Z [31]

The first one is rectangle

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3 years ago

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