EC_1 + EP_1 = EC2 + EP_2
EC_2 = 0
EC_2 = EP_1 - EP_2
EC_2 = mg(H_1 - H_2) = 0.20 kg * 9.8 m/s^2 * (3.25 m - 1.5m) = 3.43 J
Answer:
3.98V
Explanation:
Given
Pontential difference V as 3v
Energy delivered is 30%,
Recall that Enery E=1/2cv^2 from this E=V^2(since Current C is not provided we can assume a value 2)
So E=V^2
E=3^2=9
At full charge E=9,30%of 9,0.3*9=2.7 energy in capacitor is 9-2.7=6.3
But E=V^2
✓E=V
✓6.3=3.98V
Answer:
It is calculated by dividing Resistance, R, by Inductive reactance, XL.
Explanation:
Q is called the Q factor of a resonance circuit. In a parallel resonance circuit, it is calculated by finding the ratio of the power stored in the circuit to the power distributed in the circuit. It is a way of measuring the quality of a circuit or how effective the circuit is.
Q factor is the inverse in the resonance series circuit.
Q factor of a resonance parallel circuit,
<h3>
Q = R/XL</h3>
R = Resistance
XL = Inductive reactance
Answer:
0.015 atm
Explanation:
The pressure of the gas can be calculated using Ideal Gas Law:

<u>Where:</u>
n: is the number of moles of the gas
R: is the gas constant = 0.082 L*atm/(K*mol)
V: is the volume of the container = 1.64 L
T: is the temperature
We need to find the number of moles and the temperature. The number of moles is:

<u>Where:</u>
M: is the molar mass of the N₂ = 14.007 g/mol*2 = 28.014 g/mol
m: is the mass of the gas = 0.226 g

Now, the temperature can be found using the following equation:
<u>Where:</u>
R: is the gas constant = 0.082 L*atm/K*mol = 8.314 J/K*mol
: is the root-mean-square speed of the gas = 182 m/s
By solving the above equation for T, we have:
Finally, we can find the pressure of the gas:

Therefore, the pressure of the gas is 0.015 atm.
I hope it helps you!