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2 years ago

Perpendicular parking spaces require turning at a ______-degree angle.

1 answer:

7 0

Perpendicular means at 90 degree angle. so,
Perpendicular parking spaces require turning at a 90 degree angle.

When you are going to park perpendicularly, you need a distance of 7 to 8 feet from the vehicle you are parking next to, and when you are parking parallel, you need 5 feet distance from the vehicle you are parking next to.

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Which substance is used in fertilizers?

mezya [45]

Nitric acid (NHO3) because plants need nitrogen to survive, hope this helped.

3 0

3 years ago

Read 2 more answers

About how long will a 2-m¤ star live as a main-sequence star quizle

tia_tia [17]

It's mass and its age.
About how long will a 2-M star live as a main-sequence star.
1 billion years.
A low mass red giant star's energy comes from.

8 0

2 years ago

A subatomic particle X spontaneously decays into two particles, A and B, each of rest energy 1.40 × 10^2 MeV. The particles fly

adoni [48]

Answer:

E = 389 MeV

Explanation:

The total energy of particle A, will be equal to the sum of rest mass energy and relative energy of particle A. Therefore,

Total Energy of A = E = Rest Mass Energy + Relative Energy

Using Einstein's Equation: E = mc²

E = m₀c² + mc²

From Einstein's Special Theory of Relativity, we know that:

m = m₀/[√(1-v²/c²)]

Therefore,

E = m₀c² + m₀c²/[√(1-v²/c²)]

E = m₀c²[1 + 1/√(1-v²/c²)]

where,

m₀c² = rest mass energy = 140 MeV

v = relative speed = 0.827 c

Therefore,

E = (140 MeV)[1 + 1/√(1 - (0.827c)²/c²)]

E = (140 MeV)(2.78)

E = 389 MeV

6 0

2 years ago

HEEEEELP!!!!!! :((( help me with this exercise.

kirill [66]

Answer:

See the graph attached with the vectors.

Explanation:

The exercise is to draw the corresponding vectors:

$2\vec a\\\\3\vec c\\\\3\vec d\\\\3\vec f\\\\2\vec b$

Every one is the multiplication of a scalar by a vector.

The result of multiplying a scalar by a vector is a vector with the same direction of the original vector enlarged in a factor equal to the scalar magntitude.

Thus, in a graph the resulting vector is represented with a parallel arrow and pointing in the same direction as the original vector but with a length equal to the original length multiplied by the magnitude of the scalar.

For instance, the vector $2\vec a$ is represented with an arrow in the same direction of $\vec a$ and with twice its length.

The figure attached contains the five requested vectors using the procedure explained above.

7 0

2 years ago

You wish to produce an emf of 41.0 mV using an inductor whose inductance is 13.0 H. You start with a current of 1.50 mA through

Molodets [167]

Answer:

The current through the inductor at the end of 2.60s is 9.7 mA.

Explanation:

Given;

emf of the inductor, V = 41.0 mV

inductance of the inductor, L = 13 H

initial current in the inductor, I₀ = 1.5 mA

change in time, Δt = 2.6 s

The emf of the inductor is given by;

$V = L\frac{di}{dt} \\\\V = \frac{L(I_1-I_o)}{dt} \\\\L(I_1-I_o) = V*dt\\\\I_1-I_o = \frac{V*dt}{L}\\\\I_1 = \frac{V*dt}{L} + I_o\\\\I_1 = \frac{41*10^{-3}*2.6}{13} +1.5*10^{-3}\\\\I_1 = 8.2*10^{-3} + 1.5*10^{-3}\\\\I_1 = 9.7 *10^{-3} \ A\\\\ I_1 = 9.7 \ mA$

Therefore, the current through the inductor at the end of 2.60 s is 9.7 mA.

6 0

2 years ago