We have that for the Question, it can be said that With respect to this axis, the magnitude of the torque due to the weight and ,the thrust is
From the question we are told
The figure shows a jet engine suspended beneath the wing of an <em>airplane</em>. The weight of the <em>engine </em>is 14900 N and acts as shown in the <em>figure</em>. In flight the engine produces a thrust of 61500 N that is parallel to the ground. The rotational axis in the <em>figure </em>is <em>perpendicular </em>to the plane of the paper. With respect to this axis, find the <em>magnitude </em>of the torque due to (a) the <em>weight </em>and (b) the <u>thrust</u>.
a)
Generally the equation for the <u>Torque </u>due to weight is mathematically given as
TW=19740N-m
b)
Generally the equation for the <em>Torq</em>ue due to thrust is mathematically given as
TT=130387.39N-m
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Answer:
a)
b)
Explanation:
From the question we are told that:
Wire Length
Resistance
Force
Power
a)
Generally the equation for Power is mathematically given by
Therefore
b)
Generally the equation for Magnetic Field is mathematically given by
To solve this problem we will use the concepts related to Magnification. Magnification is the process of enlarging the apparent size, not physical size, of something. This enlargement is quantified by a calculated number also called "magnification".
The overall magnification of microscope is
Where
N = Near point
l = distance between the object lens and eye lens
= Focal length
= Focal of eyepiece
Given that the minimum distance at which the eye is able to focus is about 25cm we have that N = 25cm
Replacing,
Therefore the correct answer is C.
To solve this problem it is necessary to apply the law of Malus which describes the change in the Intensity of Light when it crosses a polarized surface.
Mathematically the expression is given as
Where,
= Initial Intensity
I = Final Intensity after pass through the polarizer
= Angle between the polarizer and the light
Since it is sought to reduce the intensity by half the relationship between the two intensities will be given as
Using the Malus Law we have,
Angle with respect to maximum is