A 10 kg box rests on the ground. What is the weight of the box? __ N
2 answers:
Explanation:
1. Mass of the box, m = 10 kg
Weight of an object is equal to the product of its mass and acceleration due to gravity. Its expression is given by :
W = mg
W = 98 N
2. The normal force acting on an object is equal to its weight. So, N = 98 N
3. If the box is pushed to the left with 20 N of force and it is not moving, then there is a force acting on it which is called frictional force. The static friction force have magnitude of 20 N and it is acting in opposite direction of motion.
4. When the pushing force is increased to 40 N and the box begins to move, then the maximum static frictional force is equal to applied force i.e. 40 N.
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Answer:
The minimum coefficient of friction required is 0.35.
Explanation:
The minimum coefficient of friction required to keep the crate from sliding can be found as follows:
Where:
μ: is the coefficient of friction
m: is the mass of the crate
g: is the gravity
a: is the acceleration of the truck
The acceleration of the truck can be found by using the following equation:
Where:
d: is the distance traveled = 46.1 m
: is the final speed of the truck = 0 (it stops)
: is the initial speed of the truck = 17.9 m/s
If we take the reference system on the crate, the force will be positive since the crate will feel the movement in the positive direction.
Therefore, the minimum coefficient of friction required is 0.35.
I hope it helps you!