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2 years ago

What is the value of acceleration due to gravity at the pole, equator and the centre of the earth

Physics

1 answer:

fgiga [73]2 years ago

7 0

Answer:

In combination, the equatorial bulge and the effects of the surface centrifugal force due to rotation mean that sea-level gravity increases from about 9.780 m/s2 at the Equator to about 9.832 m/s2 at the poles, so an object will weigh approximately 0.5% more at the poles than at the Equator.

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Example: What power of spectacle lens is needed to correct the vision of a nearsighted person

Aleksandr [31]

<h3>Concave or diverging lens is needed correct the vision of a nearsighted person whose far point is 30.0 cm</h3>

<em><u>Solution:</u></em>

Nearsighted person will not be able to see the distant objects clearly

Now, we want the near sighted person to see the distant objects clearly

<em><u>The lens equation is given as:</u></em>

$P = \frac{1}{d_o} + \frac{1}{d_i}$

For distant vision, $d_0 = \infty$

$d_i = image\ distance\\\\d_0 = lens\ to\ retina\ distance$

The image of 30 cm from eye will be 28.5 cm to left of spectacle lens

Therefore,

$d_i = -28.5\ cm = 0.285\ meter$

From lens equation,

$P = \frac{1}{ \infty } + \frac{1}{-0.285\ meter}\\\\P = 0 - 3.51 \\\\P = -3.51\ diopter$

The negative power -3.51 D denotes that a concave or diverging lens is needed

4 0

3 years ago

Have the rest of my points ( 100 points)<br> SAY SOMETHING NICE DOWN BELOW AND FREE BRAINLEIST

Mashcka [7]

Answer:

Explanation:

hi how was your day?

stay safe hope you have a good day

6 0

3 years ago

Read 2 more answers

Is the the last half of the month waxing or waning( talking about moon phases

rewona [7]

Its not really definable. Say, you can have a full moon on the last day of November, and have the waning phases throughout the first half. Or you can have a new moon on the last day of December, and have the waxing phases during the first half of the month.
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5 0

3 years ago

A North American tourist takes his 26.0 W, 120 V AC razor to Europe, finds a special adapter, and plugs it into 220 V AC. Assumi

Irina-Kira [14]

Explanation:

For North America,

Power, P = 26 W

Voltage of AC razor, V = 120 V

For Europe,

Voltage of AC razor, V' = 220 V

The power of razor in North America is given by :

$P=\dfrac{V^2}{R}\\\\R=\dfrac{V^2}{P}\\\\R=\dfrac{120^2}{26}\\\\R=553.84\ \Omega$

Let P' is the power consumed by razor in Europe. Now,

$P'=\dfrac{V'^2}{R}\\P'=\dfrac{220^2}{553.84}\\\\P'=87.38\ \Omega$

So, the razor consumed 87.38 watts of power as it is ruined.

7 0

3 years ago

Please need help on this thank you

lys-0071 [83]

I am pretty sure it is B....

6 0

3 years ago