2 years ago

What is the value of acceleration due to gravity at the pole, equator and the centre of the earth

1 answer:

7 0

Answer:

In combination, the equatorial bulge and the effects of the surface centrifugal force due to rotation mean that sea-level gravity increases from about 9.780 m/s2 at the Equator to about 9.832 m/s2 at the poles, so an object will weigh approximately 0.5% more at the poles than at the Equator.

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Se lanza una pelota de hule elástica de masa mA con una velocidad VAi contra la puerta trasera de un camión muy pesado de masa m

miv72 [106K]

Answer:

$v_{A}=v_{Ai}$

Explanation:

The total momentum of the system must conserve by the law of momentum conservation.

$p_b=p_a\\\\m_Av_{Ai}+m_Bv_{Bi}=m_Av_{A}+m_Bv_{B}$ ( 1 )

If you consider the shock between the ball and the truck as totally elastic, and also if the truck is much more massive than the ball, you can assume that the truck does not move when the ball hits it.

Then the truck is always at rest

Hence, you have in the expression ( 1 ):

$m_Av_{Ai}+0=m_Av_{A}+0\\\\v_{Ai}=v_{A}$