The question is incomplete. The complete question is :
To measure the effective coefficient of friction in a bone joint, a healthy joint (and its immediate surroundings) can be removed from a fresh cadaver. The joint is inverted, and a weight is used to apply a downward force F⃗ d on the head of the femur into the hip socket. Then, a horizontal force F⃗ h is applied and increased in magnitude until the femur head rotates clockwise in the socket. The joint is mounted in such a way that F⃗ h will cause clockwise rotation, not straight-line motion to the right. The friction force will point in a direction to oppose this rotation.
Draw vectors indicating the normal force n⃗ (magnitude and direction) and the frictional force f⃗ f (direction only) acting on the femur head at point A.
Assume that the weight of the femur is negligible compared to the applied downward force.
Draw the vectors starting at the black dot. The location, orientation and relative length of the vectors will be graded
Solution :
The normal force represented by N is equal to the downward force,
which is equal in magnitude but it is opposite in direction.
Also the frictional force acts always to oppose the motion because the bone starts moving in a clockwise direction. The frictional force that will be applied to the right direction so that the movement or the rotation at A is opposed.
The fundamental frequency of the tube is 0.240 m long, by taking air temperature to be
C is 367.42 Hz.
A standing wave is basically a superposition of two waves propagating opposite to each other having equal amplitude. This is the propagation in a tube.
The fundamental frequency in the tube is given by

where, 
Since, T=37+273 K = 310 K
v = 331 m/s

Using this, we get:

Hence, the fundamental frequency is 367.42 Hz.
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The speed of sound at sea level is 340.29 m/s (meters per seconds).
Answer:
E.two angles are vertical angles if, and only if they are not adjacent angles
Answer:
Part A
Newton's 3rd law states that action and reaction are equal and opposite, mathematically, we have;
= -
Where;
= The action force
= The reaction force
Part B
The law indicates that the force with which a rocket ship uses in taking off from the Earth,
is equal in magnitude, and opposite in direction to the reaction force of the Earth to the motion of the rocket, (-)
Part C
The law is a universal law, and it will also affect the rocket ship in space, as the force of the jet from the exhaust is directed towards Earth while in space, the rocket is propelled deeper into space
Explanation: