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Olin [163]
2 years ago
11

What is the value of acceleration due to gravity at the pole, equator and the centre of the earth

Physics
1 answer:
fgiga [73]2 years ago
7 0

Answer:

In combination, the equatorial bulge and the effects of the surface centrifugal force due to rotation mean that sea-level gravity increases from about 9.780 m/s2 at the Equator to about 9.832 m/s2 at the poles, so an object will weigh approximately 0.5% more at the poles than at the Equator.

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How can you tell if the force is attractive or repulsive in electrostatics?
Anni [7]
The electrostatic force of attraction or repulsion is can be found as follows,

let us consider 2 bodies in gravitational field of earth. Let the distance between those two bodies is equal to r meters. The charge on the first body is Q1 and charge on second body is Q2.
By columbs force, <u>F   </u><u /><u>α Q1×Q2</u><u>
</u>                                   r²
F=<u>k Q1×Q2 </u>                  where k-gravitational constant.
<u />        r²

Ask me, if you have any doubt regarding this.
5 0
4 years ago
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List three things that are found in the universe.
Rzqust [24]

Answer: humans, oxygen, food. Or if you taking about space, there are planets, stars, and galaxys.

Explanation:

I hope this helps!! Can I be brainliest I’ve never before!

5 0
3 years ago
Does air resistance affect the motion of a falling object differently when the initial velocity of the object is greater?
DIA [1.3K]
Yes. Even greater. Air resistance or drag becomes harder the faster an object goes. This is why when cars reach their max speed they don't accelerate as fast, because they are pushing harder against the wind. If I take a tennis ball and shoot it down a bottomless pit, a 400 kph, the drag will slow the ball down till it reaches terminal velocity. 
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3 years ago
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If the coefficient of kinetic friction between tires and dry pavement is 0.84, what is the shortest distance in which you can st
liberstina [14]

Answer:

The shortest distance in which you can stop the automobile by locking the brakes is 53.64 m

Explanation:

Given;

coefficient of kinetic friction, μ = 0.84

speed of the automobile, u = 29.0 m/s

To determine the  the shortest distance in which you can stop an automobile by locking the brakes, we apply the following equation;

v² = u² + 2ax

where;

v is the final velocity

u is the initial velocity

a is the acceleration

x is the shortest distance

First we determine a;

From Newton's second law of motion

∑F = ma

F is the kinetic friction that opposes the motion of the car

-Fk = ma

but, -Fk = -μN

-μN = ma

-μmg = ma

-μg = a

- 0.8 x 9.8 = a

-7.84 m/s² = a

Now, substitute in the value of a in the equation above

v² = u² + 2ax

when the automobile stops, the final velocity, v = 0

0 = 29² + 2(-7.84)x

0 = 841 - 15.68x

15.68x = 841

x = 841 / 15.68

x = 53.64 m

Thus, the shortest distance in which you can stop the automobile by locking the brakes is 53.64 m

4 0
3 years ago
I need help on #9 (it's side ways sorry...)
Gennadij [26K]
<span>All of these are directly proportional to each other, meaning that if one goes up or down, they all do the same.
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4 years ago
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