Answer:
50 square units
Step-by-step explanation:
Using the formula provided, 
, substituting the height (5), b1 (8) and b2 (12), we can solve for the formula.
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Answer:
0
Step-by-step explanation:
- 0 correct
- 2 incorrect
- 4 incorrect
- 8 incorrect
We are given with
dimensions of wheelbarrow = 2ft x 3ft x 1.5 ft
dimensions of truck = 11 ft x 8 ft x 6 ft
The volume of the wheelbarrow is 2(3)(1.5) = 9 ft3
The volume of the truck is 11(8)(6) = 528 ft3
70% of this is
528 ft3 (0.7) = 369.6 ft3
Dividing this by the volume of the wheelbarrow
369.6 ft3 / 9 ft3 = 41.07
He would need to use the wheelbarrow 42 times.
Answer:
108,000 joules
Step-by-step explanation:
Kinetic energy, k = 1/2 mv^2
Where,
m = mass of the object in kilogram
v = velocity in meters per seconds
If
Velocity of an object = 20 meters per seconds
Kinetic energy = 48,000 joules
Solve for m
k = 1/2 mv^2
48,000 = 1/2 × m × 20^2
48,000 = 1/2 × m × 400
48,000 = 200m
m = 48,000 / 200
m = 240 kg
If it speeds up to 30 meters per second, then what is its new kinetic energy?
k = 1/2 mv^2
Using m = 240 kg
k = 1/2 mv^2
= 1/2 × 240 × 30^2
= 1/2 × 240 × 900
= 216,000 / 2
= 108,000 joules
The new kinetic energy = 108,000 joules
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