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Gelneren [198K]
4 years ago
5

How does a conductivity apparatus test whether a solution has ionic or covalent substances in it?

Chemistry
2 answers:
Stels [109]4 years ago
5 0

Answer

When a solution is used with a conductivity apparatus and is ionic,Ions complete the flow of electrons to form a circuit.

Explanation

Covalent compounds are those which are made up by sharing of electrons between them and the electro-negativity of the elements which form covalent compounds are nearly same that is they are generally non-polar in nature whereas ionic compounds are formed by complete transfer of electrons from one element to the other and thus resulting in formation of ions of opposite charges that is cation (with positive charge) and anion (with negative charge). There is a large difference in electronegativity of the element involved in the formation of ionic compounds. They are held together by electrostatic force of attraction between them.


The conductivity of a substance is determined by the flow of electric charge. When the charged particles move that are present in the ionic compounds only in the conductivity apparatus they complete the circuit by the flow of electrons.Hence, a conductivity apparatus test whether a solution has ionic or covalent substances in it as ions complete the flow of electrons to form a circuit.




SashulF [63]4 years ago
4 0

Answer:

Explanation:

Covalent compounds are formed as a result of sharing of electrons (called shared pair) between the constituent atoms. One of the properties of covalent compounds is that they are poor conductors of electricity as they do not allow the passage of electricity through them.

Ionic compounds are formed as a result of the transfer of electrons. Here, one atom transfers its valence electron(s) to become positively charged (cations) while the other receives the transferred electron(s) to become negatively charged (anions). When ionic compounds/substances are dissolved in water, these charged particles carry electric charges when electricity is passed through them hence they are good conductors of electricity when dissolved in water. Solutions that allow for the passage of electric current in it are called electrolytes.

It is these ions in the electrolyte that allow for conduction in conductivity apparatus. When electric current is passed in the conductivity apparatus, the presence of ions (in the electrolyte) help to carry the electric current and hence completes the conductivity apparatus circuit. However, if the solution is a covalent solution, electric current is not passed and the circuit is not completed.

if the conductivity apparatus have a light bulb, when the circuit is completed, the bulb becomes lit (due to the passage of electric current in the solution) but when the circuit is not completed, the bulb is not lit (as a result of non-passage of electric current).

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Consider the reaction for the dissolution of solid magnesium hydroxide.
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Answer:

Molar solubility is 1.12x10⁻⁴M

Explanation:

The dissolution of magnesium hydroxide is:

Mg(OH)₂(s) ⇄ Mg²⁺ + 2OH⁻

The molar solubility represents the moles of the solid that the solution can dissolve, that could be written as:

Mg(OH)₂(s) ⇄ X + 2X

<em>Where X is solubility.</em>

<em />

If you obtained a [OH⁻] = 2.24x10⁻⁴M and you know [OH⁻] = 2X:

2X = 2.24x10⁻⁴M

X = 2.24x10⁻⁴M/2

X =1.12x10⁻⁴M

<h3>Molar solubility is 1.12x10⁻⁴M</h3>
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How much aluminum oxide in grams is produced from the reaction of 3.5 moles of oxygen with 4.5 moles of aluminum?
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Answer:

The mass of 3.5 moles of Ca is 140 g to two significant figures

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3 years ago
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Explanation:
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3 years ago
A 10.8ml sample of sulfuric acid titrated with 80.0 ml of 0.200 m mg solution. What is the concentration of the sample given the
IRISSAK [1]

Answer:

1.48 M

Explanation:

Step 1:

The balanced equation for the reaction. This is given below:

Mg + H2SO4 —> MgSO4 + H2

Step 2:

Determination of the number of mole of Mg in 80.0 mL of 0.200 M Mg solution. This is illustrated below:

Molarity of Mg = 0.200 M

Volume of solution = 80 mL = 80/1000 = 0.08L

Mole of Mg =?

Molarity = mole /Volume

0.2 = mole /0.08

Mole = 0.2 x 0.08

Mole of Mg = 0.016 mole.

Step 3:

Determination of the number of mole of H2SO4 that reacted. This is illustrated below:

Mg + H2SO4 —> MgSO4 + H2

From the balanced equation above,

1 mole of Mg reacted with 1 mole of H2SO4.

Therefore, 0.016 mole of Mg will also react with 0.016 mole of H2SO4.

Step 4:

Determination of the concentration of the acid.

Mole of H2SO4 = 0.016 mole.

Volume of acid solution = 10.8 mL = 10.8/1000 = 0.0108 L

Molarity =?

Molarity = mole /Volume

Molarity = 0.016/0.0108

Molarity of the acid = 1.48 M

Therefore, the concentration of acid is 1.48 M

8 0
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