Answer:
1837.89 Lt
Explanation:
The chemical reaction for this situation is:
NaHCO₃ + HCl → NaCL + H₂O + CO₂ ₍g₎
Where the mola mass we need are:
M NaHCO₃ = 84 g/mol
M CO₂ = 44 g/mol
As we have 6.00 Kg of sodium bicarbonate, then:
6 Kg NaHCO₃ = 71.43 moles of NaHCO₃
Due the stoichiometry of this chemaicl reaction:
1 mol NaHCO₃ = 1 mol CO₂
71.43 moles NaHCO₃ = 71.43 moles CO₂
And considering that CO₂ is an ideal gas, we can use the following formula:
PV=nRT
V = (nRT)/P
n = 71.43 mol
R = 0.083 Ltxatm(molxK)
T = 37°C = 310 K
P = 1 atm
So: V = (71.43x0.083x310)/1
V CO₂ = 1837.89 Lt
Answer: 1.5% w/v
Solution: (60mL)(2%) = (80mL)(x)
X = 1.5%
Answer:
you hear
Explanation:
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The number of moles of carbon dioxide produced will be 8.6 moles.
<h3>Stoichiometri mole ratios</h3>
First, let's look at the balanced equation of the reaction. The complete combustion of ethanol gives carbon dioxide and water as follows:
We can see from the equation that the burning of 1 mole of ethanol produces 2 moles of carbon dioxide. In other words, the mole ratio is 1:2.
Thus, with 4.3 moles of ethanol, the amount, in moles, of carbon dioxide that will be produced will be:
4.3 x 2 = 8.6 moles
In other words, 8.6 moles of carbon dioxide will be produced from the complete combustion of 4.3 moles of ethanol.
More on stoichiometric mole ratios can be found here: brainly.com/question/15053457
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