A and C are incorrect because they are not complete transfer of valence electrons. Ionic bonds best to form a neutral molecule
The pH of the buffer is 6.1236.
Explanation:
The strength of any acid solution can be obtained by determining their pH. Even the buffer solution strength of the weak acid can be determined using pH. As the dissociation constant is given, we can determine the pKa value as the negative log of dissociation constant value.
![pKa=-log[H] = - log [ 5.66 * 10^{-7}]\\ \\pka = 7 - log (5.66)=7-0.753=6.247\\\\pka = 6.247](https://tex.z-dn.net/?f=pKa%3D-log%5BH%5D%20%3D%20-%20log%20%5B%205.66%20%2A%2010%5E%7B-7%7D%5D%5C%5C%20%5C%5Cpka%20%3D%207%20-%20log%20%285.66%29%3D7-0.753%3D6.247%5C%5C%5C%5Cpka%20%3D%206.247)
The pH of the buffer can be known as
![pH = pK_{a} + log[\frac{[A-]}{[HA]}}]](https://tex.z-dn.net/?f=pH%20%3D%20pK_%7Ba%7D%20%2B%20log%5B%5Cfrac%7B%5BA-%5D%7D%7B%5BHA%5D%7D%7D%5D)
The concentration of ![[A^{-}] = Moles of [A]/Total volume = 0.608/2 = 0.304 M\\](https://tex.z-dn.net/?f=%5BA%5E%7B-%7D%5D%20%3D%20Moles%20of%20%5BA%5D%2FTotal%20volume%20%3D%200.608%2F2%20%3D%200.304%20M%5C%5C)
Similarly, the concentration of [HA] = 
Then the pH of the buffer will be
pH = 6.247 + log [ 0.304/0.404]

So, the pH of the buffer is 6.1236.
Solutions 1 and 3 because they are strong acids and a strong base. <u>Option A.</u>
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Strong acids and strong bases are completely ionized in an aqueous solution. Weak acids and weak bases also ionize, but only partially and the reaction is reversible. So you know if an acid or base is strong or weak. A simple way to determine strength is to add the acid or base to water. A higher reactivity means a stronger acid or base.
One of the simplest tests to determine whether a solution is an acid or base is the litmus paper test. To do this, dip a special strip of paper so-called litmus paper into the solution and observe the color of the paper. Litmus paper turns red in acidic solutions and blue in basic solutions. Sodium hydroxide is the strongest base because it completely dissociates to form sodium and hydroxide ions. These hydroxide ions are further treated with hydrogen ions by an acid to completely ionize the hydrogen ions.
Learn more about Experiment here:-https://brainly.ph/question/672153
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