<h3>
Answer:</h3>
825 mL
<h3>
Explanation:</h3>
<u>We are given;</u>
- Molarity of HCl is 0.200 M
- Mass of CaCO₃ is 8.25 g
- The equation of the reaction as;
CaCO₃ + 2HCl → CaCl₂ + H₂O + CO₂
We are required to calculate the volume of the Acid that reacted.
<h3>Step 1: Determine the moles of CaCO₃ that reacted;</h3>
We know that;
Moles = Mass ÷ molar mass
Molar mass CaCO₃ is 100.1 g/mol
Therefore;
Moles of CaCO₃ = 8.25 g ÷ 100.1 g/mol
= 0.0824 moles
<h3>Step 2: Determine the moles of HCl that reacted;</h3>
From the reaction, 1 mole of CaCO₃ reacts with 2 moles of HCl
Therefore;
Moles of HCl = Moles of CaCO₃ × 2
= 0.0824 moles × 2
= 0.1648 moles
= 0.165 moles
<h3>Step 3: Determine the volume of HCl </h3>
We know that, Molarity = Moles ÷ Volume
Rearranging the formula;
Volume = Moles ÷ Molarity
Therefore;
Volume of HCl = 0.165 moles ÷ 0.200M
= 0.825 L
But, 1 L = 1000 mL
= 825 mL
Therefore, the volume of HCl that reacted with CaCO₃ 825 mL
