Answer:
A precipitate will be formed
Explanation:
The Ksp equilibrium of Fe(OH)₃ is:
Fe(OH)₃ (s) ⇄ Fe³⁺(aq)+ 3OH⁻(aq)
And its expression is:
Ksp = 4x10⁻³⁸ = [Fe³⁺] [OH⁻]³
<em>Where the concentrations are concentrations in molarity in equilibrium,</em>
We can write Q as:
Q = [Fe³⁺] [OH⁻]³
<em>Where [] are actual concentrations in molarity of each specie.</em>
<em />
When Q>= Ksp; a precipitate is formed,
When Q< Ksp no precipitate is produced:
[OH⁻] = [NaOH] = 1.0x10⁻⁴M
[Fe²⁺] = 2.50x10⁻²g * (1mol / 179.85g) / 0.100L = 1.39x10⁻³M
<em>179.85g/mol is molar mass of Fe(NO₃)₂ and the volume of the solution is 0.100L = 100mL</em>
<em />
Q = [Fe³⁺] [OH⁻]³
Q = [ 1.39x10⁻³] [ 1.0x10⁻⁴]³
Q = 3.8x10⁻¹⁵
As Q >> Ksp; A precipitate will be formed
%error = |(original value - mistaken value)| / original value * 100%
Original value = 1.2 x 10^-12
Mistaken value = 1.7 x 10^-10
%error = | [(1.2 x 10^-12) - (1.7 x 10^-10)] | / 1.2 x 10^-12 x 100%
%error = (1.688 x 10^-10 / 1.2 x 10^-12) x 100%
%error = 1.172222222 x 10^17
Answer:Vrms is 149.7266 m/sec
Explanation:The root means square velocity of a gas can be calculated as follows:
Vrms =
where:
R is the ideal gas constant = 8.3145
T is absolute temperature = -55 + 273 = 118 degrees kelvin
M is the molar mass of the gas = 131.293 grams = 0.131293 kg
Substituting with these givens in the above equation, we would find that the Vrms is 149.7266 m/sec
Hope this helps :)
Hello, I don’t see the options
Answer:
the density of lithium will be equal to: 0.582 g/cm^3
Explanation:
We have the following data:
a = 430 pm = 4.3x10^-8 cm
molar mass of lithium MM = 6.97 g/mol
Since the cubic cell of lithium is cubic centered in the face, its value of Z will be equal to 4
Avogadro´s number AN = 6.022x10^23 particles/mol
using the following formula we will calculate the density of lithium:
d = (Z*MM)/(a^3*AN) = (4*6.97)/((4.3x10^-8)^3*(6.022x10^23)) = 0.582 g/cm^3
