The planet in our solar system whose orbit actually brings it inside the orbit of another planet is
1 answer:
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Answer:
6.9066 × 10⁻⁵ m
Explanation:
For constructive interference, the expression is:
Where, m = 1, 2, .....
d is the distance between the slits.
The formula can be written as:
....1
The location of the bright fringe is determined by :
Where, L is the distance between the slit and the screen.
For small angle ,
So,
Formula becomes:
Using 1, we get:
Thus, the distance between the central maximum is 3.00 cm
First bright fringe , m = 1 occur at 3.00 / 2 = 1.50 cm
Since,
1 cm = 0.01 m
y = 0.0150 m
Given L = 2.00 m
λ = 518 nm
Since, 1 nm = 10⁻⁹ m
So,
λ = 518 × 10⁻⁹ m
Applying the formula as:
<u>⇒ d, distance between the slits = 6.9066 × 10⁻⁵ m</u>
Answer:
Given that
D= 4 mm
K = 160 W/m-K
h=h = 220 W/m²-K
ηf = 0.65
We know that
For circular fin
m = 37.08
By solving above equation we get
L= 36.18 mm
The effectiveness for circular fin given as
ε = 23.52