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3 years ago

The planet in our solar system whose orbit actually brings it inside the orbit of another planet is

Physics

1 answer:

Ber [7]3 years ago

7 0

Answer:

Pluto

Explanation:

In our solar system, we have several planet. Pluto is one of the. Pluto is a planet that is highly oval shaped orbit and eccentric that brings it inside the another orbit. It get inside the orbit of Neptune. Sometimes even Neptune get far away from sun in comparison to the dwarf planet Pluto.

It is very strange happening in the world of planet. it occurs in the year of 1979 and 1999. But Pluto never ever crashed into Neptune. It happen because Neptune takes every three lapse that takes around the sun but Pluto makes only two lapse. This happening prevents two bodies from clashes.

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Square root of 40 as a fraction

AysviL [449]

Answer:

158/25

Explanation:

I really hope I helped you!!

Have a good day! :)

8 0

3 years ago

The spherical side mirror on a car is convex and has a radius of curvature of 25 cm. Another car is following, 20 m behind the m

svlad2 [7]

Answer:

(D) 0.99 cm

Explanation:

Given that the radius of curvature of the mirror is 25 cm.

And another car is following which is behind the mirror of 20 m.

$u=20m=2000cm$

Focal length is half of the radius of curvature and it is negative for convex lens.

Now the mirror formula.

$1/v+1/u=1/f$

So,

$1/v+1/2000=-1/(25/2)\\1/v=-1/2000-1/12.5\\v=-12.422cm$

Now

Magnification is,

$m=-v/u$

So,

$m=12.422/2000=0.00621$

So, Height of the image

$mh=0.00621\times 1.6 m\\mh=0.0099m\\mh=0.99cm$

Therefore, the image height is 0.99 cm.

4 0

3 years ago

135g of an unknown substance gains 9133 J of heat as it is heated from 25⁰C to 100⁰C. Using the chart below, determine the ident

telo118 [61]

Answer:

The unknown substance is Aluminum.

Explanation:

We'll begin by calculating the change in the temperature of substance. This can be obtained as follow:

Initial temperature (T₁) = 25 ⁰C

Final temperature (T₂) = 100 ⁰C

Change in temperature (ΔT) =?

ΔT = T₂ – T₁

ΔT = 100 – 25

ΔT = 75 ⁰C

Finally, we shall determine the specific heat capacity of the substance. This can be obtained as follow:

Change in temperature (ΔT) = 75 ⁰C

Mass of the substance (M) = 135 g

Heat (Q) gained = 9133 J

Specific heat capacity (C) of substance =?

Q = MCΔT

9133 = 135 × C × 75

9133 = 10125 × C

Divide both side by 10125

C = 9133 / 10125

C = 0.902 J/gºC

Thus, the specific heat capacity of substance is 0.902 J/gºC

Comparing the specific heat capacity (i.e 0.902 J/gºC) of substance to those given in the table above, we can see clearly that the unknown substance is aluminum.

7 0

3 years ago

How much heat energy in megajoules is needed to convert 7 kilograms of ice at -9c to water at 0c

Musya8 [376]

The latent heat of fusion of water is 344 j/p.This will take 344x300 or 100200 J to melt the ice. once it melted its at oc

6 0

3 years ago

Read 2 more answers

What is the equation that relate electric potential (voltage) to electric field?

erma4kov [3.2K]

V= I x R
I= V / R
r= V / I

7 0

3 years ago