10 cm. Because for each cm is 10 mm.
Answer:
Hay 160 maneras
Step-by-step explanation:
Para calcular de cuántas maneras se puede seleccionar x elementos de un grupo de n elementos podemos usar la siguiente fórmula:
Si vas a elegir 3 personas de entre 6 matrimonios y dos miembros de la misma pareja no pueden ser elegidos, entonces podemos decir que se está eligiendo 3 matrimonios y en cada matrimonio se está eligiendo un representante.
Entonces, podemos calcular de cuántas maneras se puede escoger 3 matrimonios de los 6, así:
Adicionalmente, para cada uno de los 3 matrimonios hay 2 opciones para ser representantes. Esto significa que hay 
maneras de escoger representantes en cada una de las 20 formas calculadas anteriormente.
Por lo tanto se puede formar el grupo de 3 personas de 160 maneras diferentes:
Answer:
Step-by-step explanation:
Given triangles are similar, so we setup a proportion
(140-x)/81 = x/9
solving gives x = 14
AC = 140-x = 140-14 = 126
Answer:
3 tents hold 2 campers
Step-by-step explanation:
The given relations can be expressed as a single equation in the number of 2-camper tents.
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Let x represent the number of 2-camper tents. Then the number of 4-camper tents is 6-x, and the total number of campers in tents is ...
2x +4(6 -x) = 18
-2x +24 = 18
-2x = -6 . . . . . . subtract 24
x = 3 . . . . . . . divide by -2
Exactly 3 tents hold 2 campers.
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<em>Additional comment</em>
The other 3 tents hold 4 campers.
Another way to consider this is to assume that all tents hold 2 campers, and then realize there are 18 -6×2 = 6 campers left over. If these are placed 2 per tent, then there will be 6/2 = 3 tents with 4 campers. The remaining 3 tents will have 2 campers.
The function of the length z in meters of the side parallel to the wall is A(z) = z/2(210 - z)
<h3>How to write a function of the length z in meters of the side parallel to the wall?</h3>
The given parameters are:
Perimeter = 210 meters
Let the length parallel to the wall be represented as z and the width be x
So, the perimeter of the fence is
P = 2x + z
This gives
210 = 2x + z
Make x the subject
x = 1/2(210 - z)
The area of the wall is calculated as
A = xz
So, we have
A = 1/2(210 - z) * z
This gives
A = z/2(210 - z)
Rewrite as
A(z) = z/2(210 - z)
Hence, the function of the length z in meters of the side parallel to the wall is A(z) = z/2(210 - z)
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