Answer:
since I can't see the whole shape or what the question is asking for, I'm going to assume that the shape is a square and that the question is asking for the perimeter because that appears to be the only way to get 6x–2
Step-by-step explanation:
to get the answer 6x–2, you would have to multiply the base by 2 and the height by 2 and add them together.
Answer:
third answer
Step-by-step explanation:
The end behavior of the function indicates that the leading coefficient of x is negative (as x approaches infinity, f(x) approaches negative infinity for cubic functions with negative leading coefficients). This eliminates the first 2 answers. Next, factor out the common factor from the 3rd answer and set it to 0 to see if the roots of the polynomial shown on the graph (x=-3, x=2) match that of the answer.
- factor out -2x since each term in the 3rd answer is divisible by -2x => -2x(x^2+x-6)
- set the factored polynomial equal to 0 => -2x(x^2+x-6)
- divide both sides by -2x => 0 = x^2+x-6
- factor => (x+3)(x-2) = 0
- find zeros by setting both factors equal to 0 => x=-3, x=2
This means that the 3rd answer is correct. The last answer, while having the correct leading coefficient, will produce roots of 3 and -2 instead of -3 and 2, which is shown on the graph.
Answer:
Expected number of free throws in 60 attempts:
Best player = 48
2nd best player = 45
3rd best player = 42
Step-by-step explanation:
Solution:-
- The probability that best player makes free throw, p1 = 0.8
- The probability that second-best player makes free throw, p2 = 0.75
- The probability that third-best player makes free throw, p3 = 0.70
- Total number of attempts made in free throws, n = 60.
- The estimated number of free throws that any player makes is defined by:
E ( Xi ) = n*pi
Where, Xi = Player rank
pi = Player rank probability
- Expected value for best player making the free throws would be:
E (X1) = n*p1
= 60*0.8
= 48 free throws
- Expected value for second-best player making the free throws would be:
E (X2) = n*p2
= 60*0.75
= 45 free throws
- Expected value for third-best player making the free throws would be:
E (X3) = n*p3
= 60*0.70
= 42 free throws
<h2>281.75</h2>
Step-by-step explanation:
23 [1/4 +4(36÷12)]
23 [1/4 +4×3]
23 [0.25 +12]
23 ×12.25
281.75
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