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blsea [12.9K]
3 years ago
11

A 12.8-kg monkey hangs from a cord suspended from the ceiling of an elevator. The cord can withstand a tension of 156N and break

s as the elevator accelerates. What was the magnitude of the elevator's minimum acceleration? and What was the direction of the elevator's minimum acceleration?
Physics
1 answer:
Varvara68 [4.7K]3 years ago
8 0

Answer:

2.4 m/s^2

Downward

Explanation:

We are given that

Mass of monkey=12.8 kg

Tension=156 N

We have to find the magnitude of the elevator's minimum acceleration.

T=m(g+a)

Where g=9.8 m/s^2

Substitute the values

156=12.8(a+9.8)

9.8+a=\frac{156}{12.8}=12.2

a=12.2-9.8=2.4 m/s^2

Hence, the acceleration =a=2.4 m/s^2

Direction of the elevator's minimum acceleration is downward because the elevator moves downwards.

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Pls help me l will make it brainlest ​
nikklg [1K]

Answer:

<u>0.04 °C⁻¹</u>

Explanation:

First, we need to calculate linear expansivity, then after finding that value, we can move on to finding the area expansivity.

<u />

=============================================================

Finding Linear Expansivity :

⇒ α = Final length - Original length / (Original length × ΔT)

⇒ α = 9 - 4 / (4 × 70 - 20)

⇒ α = 5 / 5 × 50

⇒ α = <u>0.02</u>

============================================================

Finding Area Expansivity :

⇒ Area Expansivity = 2 × Linear Expansivity

⇒ β = 2 × α

⇒ β = 2 × 0.02

⇒ β = <u>0.04 °C⁻¹</u>

3 0
1 year ago
Read 2 more answers
Which statement accurately describes a sample of water during parts a and c of the heating curve
vivado [14]

Answer:

A and C is about 12 cm away from each other.

Explanation:

5 0
3 years ago
Read 2 more answers
The Hall effect can be used to determine the density of mobile electrons in a conductor. A thin strip of the material being inve
solmaris [256]

Answer:

the density of mobile electrons in the material is 3.4716 × 10²⁵ m⁻³

Explanation:

Given the data in the question;

we make use of the following expression;

hall Voltage VH = IB / ned

where I = 2.25 A

B = 0.685 T

d =  0.107 mm =  0.107 × 10⁻³ m

e = 1.602×10⁻¹⁹ C

VH = 2.59 mV = 2.59 × 10⁻³ volt

n is the electron density

so from the form; VH = IB / ned

VHned = IB

n = IB / VHed

so we substitute

n = (2.25 × 0.685) / ( 2.59 × 10⁻³ × 1.602×10⁻¹⁹ × 0.107 × 10⁻³ )

n = 1.54125 /  4.4396226 × 10⁻²⁶

n = 3.4716 × 10²⁵ m⁻³

Therefore, the density of mobile electrons in the material is 3.4716 × 10²⁵ m⁻³

5 0
3 years ago
4. How much time does it take for a student running at a speed of 5 m/s to cover a distance of 2,000 m?
Monica [59]

Answer:

6 Minutes 40 Seconds or 400 Seconds

Explanation:

Time to cover a distance of 5m = 1 Second

Time to cover a distance of 2000m = 2000÷5

= 400 Seconds

After converting 400 Seconds into minutes it will become 6 minutes 40 seconds.

Those who found this helpful please give me a Thanks to support me. So, I can explain other questions more clearly. If you don't want to mark me Brainliest don't mark. But, please give me a Thanks.

6 0
3 years ago
Someone help please.....
Westkost [7]

Answer:

0.0928km/min (4dp)

Explanation:

To find the jogger's speed in km per minute, we just need to divide the number of km jogged by the time in minutes it took to jog that distance. This will give us the distance they jogged every minute which is their speed.

4km in 32 minutes:

4/32 = 0.125km/min

2km in 22 minutes:

2/22 = 0.091 (3dp)km/min

1km in 16 minutes:

0.0625km/min

Now to find the average speed of these 3 speeds, we just add them all together and divide by how many values there are (3 values).

Average (mean)  = \frac{0.125+0.091+0.0625}{3}

Average = 0.2785/3

Average speed of jogger = 0.0928 (4dp) km/min

Hope this helped!

8 0
3 years ago
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