Explanation:
The velocity of sound depends on the density of the medium. So we need to find the density of air at each set of conditions. The density of air is:
ρ = (Pd / (Rd T)) + (Pv / (Rv T))
where Pd and Pv are the partial pressures of dry air and water vapor,
Rd and Rv are the specific gas constants of dry air and water vapor,
and T is the absolute temperature.
At the first condition:
Pv = 31.7 mmHg = 4226.3 Pa
Pd = 650 mmHg - 31.7 mmHg = 618.3 mmHg = 82433 Pa
Rv = 461.52 J/kg/K
Rd = 287.00 J/kg/K
T = 30°C = 303.15°C
ρ = (82433 / 287.00 / 303.15) + (4226.3 / 461.52 / 303.15)
ρ = 0.94746 + 0.03021
ρ = 0.97767 kg/m³
At the second condition:
Pv = 0 Pa
Pd = 650 mmHg = 86660 Pa
Rv = 461.52 J/kg/K
Rd = 287.00 J/kg/K
T = 0°C = 273.15°C
ρ = (86660 / 287.00 / 273.15) + (0 / 461.52 / 273.15)
ρ = 1.1054 + 0
ρ = 1.1054 kg/m³
The square of the velocity of sound is proportional to the ratio between pressure and density:
v² = k P / ρ
Since the atmospheric pressure is constant, we can say it's proportional to just the density:
v² = k / ρ
Using the first condition to find the coefficient:
(340)² = k / 0.97767
k = 113018.652
Now finding the velocity of sound at the second condition:
v² = 113018.652 / 1.1054
v = 319.75
Answer:
The value of d is 183.51 m.
Explanation:
Given that,
Speed of car = 34.0 m/s
Suppose The car race in the circle parallel to the ground surface is at an angle 40°
The radius of circular path
Normal force acting on the car = N
We need to calculate the value of d
Using component of normal force
The horizontal component of normal force is equal to the gravitational force.
....(I)
The vertical component of normal force is equal to the centripetal force
.....(II)
Divided equation (I) by equation (II)
Put the value of g
Put the value into the formula
Hence, The value of d is 183.51 m.
A run though an open field during a thunderstorm is the answer
D. When a substance reacts with another substance, it shows its chemical property
Answer:
it is very hard question for me sorry i cant solve it