How much thermal energy is needed to raise the temperature of 4g of water
1 answer:
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Answer:
Explanation:
a).
conc of Ca²⁺ =0.0025 M
pCa = -log(0.0025) = 2.6
logK,= 10.65 So lc = 4.47 x 10.
Formation constant of Ca(EDTA)]-z= 4.47 x 10¹⁰ At pH = 11, the fraction of EDTA that exists Y⁻⁴ is =0.81
So the Conditional Formation constant= =0.81x 4.47 x10¹⁰
=3.62x10¹⁰
b)
At Equivalence point:
Ca²⁺ forms 1:1 complex with EDTA At equivalence point,
Number of moles of Ca²⁺= Number of moles of EDTA Number of moles of Ca²⁺ = M×V = 0.00250 M × 50.00 mL = 0.125 mol
Number of moles of EDTA= 0.125 mol
Volume of EDTA required = moles/Molarity = 0.125 mol / 0.0050 M = 25.00 mL
V e= 25.00 mL
At equivalence point, all Ca²⁺ is converted to [CaY²⁻] complex. So the concentration of Ca²⁺ is determined by the dissociation of [CaY²⁻] complex.
Ca²⁺ + Y⁴ ⇄ CaY²⁻
Initial 0 0 0.001667
change +x +x -x
equilibrium x x 0.001667 - x
x = 2.15×10⁻⁷
[Ca+2] = 2.15x10⁻⁷ M
pca = —log(2 15x101= 6.7
Answer : The equilibrium concentrations of all species are, 0.05 M, 0.043 M and 0.975 M respectively.
Explanation : Given,
Moles of = 2 mole
Moles of = 1 mole
Volume of solution = 1 L
Initial concentration of = 2 M
Initial concentration of = 1 M
The given balanced equilibrium reaction is,
Initial conc. 2 M 1 M 0
At eqm. conc. (2-2x) M (1-x) M (2x) M
The expression for equilibrium constant for this reaction will be,
The for reverse reaction =
Now put all the given values in this expression, we get :
By solving the term 'x', we get :
x = 0.975
Thus, the concentrations of at equilibrium are :
Concentration of = (2-2x) M = (2 - 2 × 0.975) M = 0.05 M
Concentration of = (1-x) M = 1 - 0.975 = 0.043 M
Concentration of = x M = 0.975 M
Therefore, the equilibrium concentrations of all species are, 0.05 M, 0.043 M and 0.975 M respectively.