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Lemur [1.5K]
3 years ago
14

Match these items.

Chemistry
2 answers:
Vika [28.1K]3 years ago
4 0

1 ability to react with another substance  

2 fixed internal order

3 no definite internal order

Hope this helps

Goryan [66]3 years ago
3 0
Can u give me the brainliest?
1 ability to react with another substance
2 fixed internel order
4 no definite internal order
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2. Which of the following is not a physical property of water? It is a colorless liquid. It is composed of hydrogen and oxygen.
S_A_V [24]

The correct answer is C. Sugar dissolves in it

Hope this helps

-AaronWiseIsBae

7 0
3 years ago
Gallium arsenide, GaAs, has gained widespread use in semiconductor devices that convert light and electrical signals in fiber-op
stira [4]

Answer:

Five peaks  

Explanation:

GaAs would show two peaks:

Ga-69 + As-75 = 144

Ga-71 + As-75 = 146

Their intensities are in the ratio 60 : 40 = 100:67.

Ga₂S₂ would show three peaks:

Ga-69 + Ga-69 + 2As-75 = (Ga-69)₂(As-75)₂ = 288

Ga-69 + Ga-71 + 2As-75 = (Ga-69)(Ga-71(As-75)₂ = 290

Ga-71 + Ga-71 + 2As-75 = (Ga-71)₂(As-75)₂ = 292

Their relative intensities are in the ratio

(60 + 40)² = 60² : 2×60×40 : 40² = 3600 : 4800 : 1600 = 75 : 100 : 33

A spectrum of a mixture of GaAs and Ga₂As₂ would show five peaks:

Two at m/e 144 and 146 with intensity ratios 100: 67 and

Three at m/e 288, 290, and 292 with intensity ratios 75:100 :33.

We cannot predict the absolute sizes of the peaks because we do not know the relative amounts of GaAs and GaAs₂.

6 0
4 years ago
A first order reaction has rate constants of 4.6 x 10-2 s-1 and 8.1 x 10-2 s-1 at 0ºC and 20ºC, respectively. What is the value
Airida [17]

Answer:

D.  18,800 J/mol

Explanation:

We need to use the Arrhenius equation to solve for this problem:

k=Ae^{\frac{-E_a}{RT}, where k is the rate constant, A is the frequency factor, E_a is the activation energy, R is the gas constant, and T is the temperature in Kelvins.

We want to find the value of E_a, so let's plug some of the information we have into the equation. The gas constant we can use here is 8.31 J/mol-K.

At 0°C, which is 0 + 273 = 273 Kelvins, the rate constant k is 4.6*10^{-2}. So:

k=Ae^{\frac{-E_a}{RT}

4.6*10^{-2}=Ae^{\frac{-E_a}{8.31*273}

At 20°C, which is 20 + 273 = 293 Kelvins, the rate constant k is 8.1*10^{-2}. So:

k=Ae^{\frac{-E_a}{RT}

8.1*10^{-2}=Ae^{\frac{-E_a}{8.31*293}

We now have two equations and two variables to solve for. We just want to find Ea, so let's write the first equation for A in terms of Ea:

4.6*10^{-2}=Ae^{\frac{-E_a}{8.31*273}

A=\frac{4.6*10^{-2}}{e^{\frac{-E_a}{8.31*273}} }

Plug this in for A in the second equation:

8.1*10^{-2}=Ae^{\frac{-E_a}{8.31*293}

8.1*10^{-2}=\frac{4.6*10^{-2}}{e^{\frac{-E_a}{8.31*273}} }e^{\frac{-E_a}{8.31*293}

After some troublesome manipulation, the answer should come down to be approximately:

Ea = 18,800 J/mol

The answer is thus D.

5 0
3 years ago
When you convert feet to inches, how do you decide which portion of the conversion factor should be in the numerator and which i
Inessa05 [86]

Answer : The conversion used is, 1\text{ feet}=12\text{ inches}

Explanation :

The conversion used :

1\text{ feet}=12\text{ inches}

For example : To convert 10 feet into inches.

1\text{ feet}=12\text{ inches}

10\text{ feet}=10\text{ feet}\times \frac{12\text{ inches}}{1\text{ feet}}

                    =120\text{ inches}

From this we conclude that, the conversion factor used in the numerator and denominator for 1 feet should be, \frac{12\text{ inches}}{1\text{ feet}}

3 0
4 years ago
consider a different titrant for this exercise. suppose ca(oh)2 were used as the titrant, instead of naoh. this will make the ti
Ivan

The titrant for this exercise. suppose Ca(OH)₂ were used as the titrant, instead of NaOH. This will make the titrant twice as concentrated in hydroxide ion. the analyte will still be HC₂H₃O₂. the stoichiometry ratio of  HC₂H₃O₂ to Ca(OH)₂ is 1 : 2.

The balanced reaction of the given condition as follow :

 Ca(OH)₂   +      2HC₂H₃O₂      ------>     Ca(C₂H₃O₂)₂     +    2H₂O

from the equation it is clear that stoichiometry of Ca(OH)₂ is 1 and the stoichiometry of HC₂H₃O₂    is 2. therefore the stoichiometry ratio of  HC₂H₃O₂ to Ca(OH)₂ is 1 : 2.

Thus, The titrant for this exercise. suppose Ca(OH)₂ were used as the titrant, instead of NaOH. This will make the titrant twice as concentrated in hydroxide ion. the analyte will still be HC₂H₃O₂. the stoichiometry ratio of  HC₂H₃O₂ to Ca(OH)₂ is 1 : 2.

To learn more about stoichiometry here

brainly.com/question/13145466

#SPJ4

4 0
2 years ago
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