The correct answer is C. Sugar dissolves in it
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Answer:
Five peaks
Explanation:
GaAs would show two peaks:
Ga-69 + As-75 = 144
Ga-71 + As-75 = 146
Their intensities are in the ratio 60 : 40 = 100:67.
Ga₂S₂ would show three peaks:
Ga-69 + Ga-69 + 2As-75 = (Ga-69)₂(As-75)₂ = 288
Ga-69 + Ga-71 + 2As-75 = (Ga-69)(Ga-71(As-75)₂ = 290
Ga-71 + Ga-71 + 2As-75 = (Ga-71)₂(As-75)₂ = 292
Their relative intensities are in the ratio
(60 + 40)² = 60² : 2×60×40 : 40² = 3600 : 4800 : 1600 = 75 : 100 : 33
A spectrum of a mixture of GaAs and Ga₂As₂ would show five peaks:
Two at m/e 144 and 146 with intensity ratios 100: 67 and
Three at m/e 288, 290, and 292 with intensity ratios 75:100 :33.
We cannot predict the absolute sizes of the peaks because we do not know the relative amounts of GaAs and GaAs₂.
Answer:
D. 18,800 J/mol
Explanation:
We need to use the Arrhenius equation to solve for this problem:
, where k is the rate constant, A is the frequency factor,
is the activation energy, R is the gas constant, and T is the temperature in Kelvins.
We want to find the value of
, so let's plug some of the information we have into the equation. The gas constant we can use here is 8.31 J/mol-K.
At 0°C, which is 0 + 273 = 273 Kelvins, the rate constant k is
. So:


At 20°C, which is 20 + 273 = 293 Kelvins, the rate constant k is
. So:


We now have two equations and two variables to solve for. We just want to find Ea, so let's write the first equation for A in terms of Ea:


Plug this in for A in the second equation:


After some troublesome manipulation, the answer should come down to be approximately:
Ea = 18,800 J/mol
The answer is thus D.
Answer : The conversion used is,
Explanation :
The conversion used :

For example : To convert 10 feet into inches.



From this we conclude that, the conversion factor used in the numerator and denominator for 1 feet should be, 
The titrant for this exercise. suppose Ca(OH)₂ were used as the titrant, instead of NaOH. This will make the titrant twice as concentrated in hydroxide ion. the analyte will still be HC₂H₃O₂. the stoichiometry ratio of HC₂H₃O₂ to Ca(OH)₂ is 1 : 2.
The balanced reaction of the given condition as follow :
Ca(OH)₂ + 2HC₂H₃O₂ ------> Ca(C₂H₃O₂)₂ + 2H₂O
from the equation it is clear that stoichiometry of Ca(OH)₂ is 1 and the stoichiometry of HC₂H₃O₂ is 2. therefore the stoichiometry ratio of HC₂H₃O₂ to Ca(OH)₂ is 1 : 2.
Thus, The titrant for this exercise. suppose Ca(OH)₂ were used as the titrant, instead of NaOH. This will make the titrant twice as concentrated in hydroxide ion. the analyte will still be HC₂H₃O₂. the stoichiometry ratio of HC₂H₃O₂ to Ca(OH)₂ is 1 : 2.
To learn more about stoichiometry here
brainly.com/question/13145466
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