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3 years ago

Is it possible for an object not to be in motion and still have force acting upon it?

1 answer:

3 0

Yes,this is an example:
An apple is sitting on a desk he is not in motion but one of the forces acting upon it is gravitational pull because is not floating around, the earth gravitational pull is pulling it down to the earth's surface.

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What mass of solid that has a molar mass of 46.0 g/mol should be added to 150.0 g of benzene to raise the boiling point of benze

enyata [817]

Answer : 17.12 g

Explanation: $\Delta T =k_b\times m$

$\Delta T$ = elevation in boiling point

$k_b$ = boiling point elevation constant

m= molality

$molality=\frac{mass of solute}{molecular mass of solute\times weight of the solvent in kg}$

given $\Delta T=6.28^{\circ}C$

Molar mass of solute = 46.0 $gmol^{-1}$

Weight of the solvent = 150.0 g = 0.15 kg

Putting in the values

$molality=\frac{x}{46gmol^{-1}\times0.15kg}$

$6.28 =2.53^{\circ}Ckgmol^{-1}\frac{x}{46gmol^{-1}\times 0.15kg}$

x = 17.12 g

3 0

3 years ago

How many significant figures are in 5.40

kotykmax [81]

There are 3 significant figures in this value, all values before and after the decimal point are significant. As there is a decimal point, the zeros trailing are also significant.

4 0

3 years ago

In the reaction of sodium with oxygen

Anestetic [448]

Answer:

I think that it's b

Explanation:

please please tell me if it's the right answer

6 0

3 years ago

Read 2 more answers

A solid sample is hit with a hammer and breaks into jagged, irregular shards. What type of solid was it? A) molecular solid b) n

DaniilM [7]

I honestly don't know the answer

8 0

2 years ago

What would happen to the pressure if the volume were reduced to 0.5 l and the temperature increased to 260 ∘c?

Vsevolod [243]

<span>The ideal gas law. PV=nRT pressure x volume = moles x Faraday's constant x Temp Kelvin (C+273) Original data Pressure 1 atmosphere Volume 1 liter Temp 25C = 298K New data Volume 0.5 liter pressure X Temp 260C = 533K P1v1T1 = P2v2T2 plug and chug. (1)(1)(293) = (x)(0.5)(533) Solve for X, which is the new pressure. </span>

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3 years ago