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erma4kov [3.2K]
3 years ago
9

What is refraction? * Bending of light Reflection of light

Chemistry
2 answers:
sdas [7]3 years ago
6 0
Refraction is the bending of light (it also happens with sound, water and other waves) as it passes from one transparent substance into another. This bending by refraction makes it possible for us to have lenses, magnifying glasses, prisms and rainbows. Even our eyes depend upon this bending of light. Hope this helps!
garik1379 [7]3 years ago
4 0
It is reflection, hoped it helped
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What happens to air pressure as altitude increases
gulaghasi [49]

Answer:

the air pressure decreases

explanation

as altitude increases air pressure decreases the surface of the Earth is bottom of the ocean of the are the layer on top increase pressure so that sea levels a body is under 14.7 pounds of pressure per square inch moving up in altitude decreases weight of the air that causes the pressure

4 0
3 years ago
A reading shows a pressure measurement of 43 in. Hg. What is the equivalent pressure in psi? A. 5.73 psi B. 2223.13 psi C. 26.32
oksian1 [2.3K]
43 inHg = 43 inHg*2.54cm/in = 109.22cmHg * 10 mm/cm = 1092.2 mmHg


14.7 psi = 760 mmHg

1092.2mmHg * 14.7psi / 760 mmHg = 21.13 psi

Answer: option D. 21.13 psi
7 0
4 years ago
Read 2 more answers
A __________ ALSO IS MADE UP OF TWO OR MORE ATOMS. BUT IN THIS CASE IT CAN BE THE SAME AS WELL AS DIFFERENT
alina1380 [7]

Answer:

D

Explanation:

3 0
3 years ago
What is the pressure if 0.567 moles of gas occupy 4.5 liters at a temperature of 300.0 K?
kakasveta [241]
The answer is D. Use the equation PV=nRT
P=(.567mol)(.0821)(300K)/4.5L
3 0
3 years ago
<img src="https://tex.z-dn.net/?f=H_2PO_4%5E-%28aq%29%20%5Crightarrow%20H%5E%2B%28aq%29%20%2B%20HPO_4%5E%7B2-%7D%28aq%29" id="Te
klasskru [66]

Answer:

The pH of the buffer solution = 8.05

Explanation:

Using the Henderson - Hasselbalch equation;

pH = pKa₂ + log ( [HPO₄²-]/[H₂PO4⁻]

where pKa₂ = -log (Ka₂) = -log ( 6.1 * 10⁻⁸) = 7.21

Concentration of OH⁻ added = 0.069 M (i.e. 0.069 mol/L)

[H₂PO4⁻] after addition of OH⁻ = 0.165 - 0.069 = 0.096 M

[HPO₄²-] after addition of OH⁻ = 0.594 + 0.069 = 0.663 M

Therefore,

pH = 7.21 + log (0.663 / 0.096)

pH = 7.21 + 0.84

pH = 8.05

4 0
3 years ago
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