Following reaction takes place between LiOH and HNO3
LiOH + HNO3 → LiNO3 + H2O
Thus, 1 mole of LiOH reacts with 1 mole of HNO3 to form 1 mole of LiNO3.
Now,
Number of millimoles of LiOH consumed = <span>36.90 X 0.100 = 3.690
</span>∴Number of millimoles of HNO3 present = 3.690
<span>
Now, Molarity of HNO3 = </span>

=

= 0.0738 M
Thus, <span>
molarity of the HNO3 solution is 0.0738 M</span>
I believe it is aluminum
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They're elements. Elements are the simplest form of any substance that cannot be broken down by any chemical methods, including electrolysis or even heat. Examples include oxygen, hydrogen etc.
Answer:
1.17 grams of HCl can neutralize 2.7 grams sodium bicarbonate
Explanation:
Step 1: Data given
Mass of sodium bicarbonate = 2.7 grams
Step 2: The balanced equation
HCl + NaHCO3 ⇔ NaCl + H2O + CO2
Step 3: Calculate moles NaHCO3
moles NaHCO3 =2.7 g / 84 g/mol= 0.032 moles
Step 4: Calculate moles HCl
For 1 mol NaHCO3 we need 1 mol HCl
For 0.032 moles NaHCO3 = 0.032 moles HCl
Step 5: Calculate mass HCl
Mass HCl = moles HCl * molar mass HCl
mass HCl = 0.032 * 36.46 g/mol= 1.17 grams
1.17 grams of HCl can neutralize 2.7 grams sodium bicarbonate
Answer:
an exothermic reaction that Increase in entropy