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Simora [160]
3 years ago
15

After reviewing your answers to questions 2 and 4 above, would you define boiling point and melting point as a periodic table fa

mily trend (vertical groups), period trend (horizontal rows), or neither? Explain your answer.
Chemistry
1 answer:
Andru [333]3 years ago
8 0
The periodic table<span>, and its respective </span>melting<span> and </span>boiling points<span>. ... </span>Chemistry.2<span> The student </span>will <span>investigate and understand that the placement of elements ... </span>Families/groups<span> ... As </span>you<span> analyze </span>your <span>graph, try to </span>answer<span> the </span>following questions<span>: ... </span>period<span>. How </span>would you describe<span> the </span>trend<span> in </span>boiling point<span> as the atomic number ...</span>
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Answer:

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2.

5.

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Based on the table what conclusion can the student make about relationships between elements
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What Tennessee agency is responsible for licensing pets and ensuring that they are vaccinated for rabies?

5 0
3 years ago
Which is a better leaving group, OH or SH?
erik [133]

Answer:

OH

Explanation:

8 0
3 years ago
Read 2 more answers
how does the main function of the nervous system help the body react to internal and external stimuli??
Irina-Kira [14]
Nerves send signals to your brain from your spinal cord. If something is burning your nerves will send a pain signal from the area of the burn to your brain through you spinal cord. Then your brain sends a signal back to the nerves that there is pain and you should avoid it. Same with internal nerves and same with touch.
6 0
3 years ago
Liquid octane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 8.00 g of octane is m
DerKrebs [107]

Answer:

11.3 g of H₂O will be produced.

Explanation:

The combustion is:

2C₈H₁₈ +  25O₂→  16CO₂  +  18H₂O

First of all, we determine the moles of the reactants in order to find out the limiting reactant.

8 g / 114g/mol = 0.0701 moles of octane

37g / 32 g/mol = 1.15 moles of oxygen

The limiting reagent is the octane. Let's see it by this rule of three:

25 moles of oxygen react to 2 moles of octane so  

1.15 moles of oxygen will react to ( 1.15 . 2)/ 25 = 0.092 moles of octane.

We do not have enough octane, we need 0.092 moles and we have 0.0701 moles. Now we work with the stoichiometry of the reaction so we make this rule of three:

2 moles of octane produce 18 moles of water

Then 0.0701 moles of octane may produce (0.0701 . 18)/2= 0.631 moles of water.

We convert the moles to mass → 0.631 mol . 18 g/1mol = 11.3 g of H₂O will be produced.

4 0
3 years ago
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