A substance that is present in a reaction but not used up in the reaction is called a catalyst
Answer:
<h2>volume = 74.07 cm³</h2>
Explanation:
The volume of a substance given the density and mass can be found by using the formula

From the question
Density = 13.5 g/cm³
We must first convert the mass from kg to g
1kg = 1000 g
mass of mercury = 1000 g
Substitute the values into the above formula and solve
That's

We have the final answer as
<h3>volume = 74.07 cm³</h3>
Hope this helps you
Answer : The ratio of the protonated to the deprotonated form of the acid is, 100
Explanation : Given,

pH = 6.0
To calculate the ratio of the protonated to the deprotonated form of the acid we are using Henderson Hesselbach equation :
![pH=pK_a+\log \frac{[Salt]}{[Acid]}](https://tex.z-dn.net/?f=pH%3DpK_a%2B%5Clog%20%5Cfrac%7B%5BSalt%5D%7D%7B%5BAcid%5D%7D)
![pH=pK_a+\log \frac{[Deprotonated]}{[Protonated]}](https://tex.z-dn.net/?f=pH%3DpK_a%2B%5Clog%20%5Cfrac%7B%5BDeprotonated%5D%7D%7B%5BProtonated%5D%7D)
Now put all the given values in this expression, we get:
![6.0=8.0+\log \frac{[Deprotonated]}{[Protonated]}](https://tex.z-dn.net/?f=6.0%3D8.0%2B%5Clog%20%5Cfrac%7B%5BDeprotonated%5D%7D%7B%5BProtonated%5D%7D)
As per question, the ratio of the protonated to the deprotonated form of the acid will be:
Therefore, the ratio of the protonated to the deprotonated form of the acid is, 100
Answer:
The pressure remains constant
Explanation:
this is an example in charles law where as the temperature increases so does the volume.