Yellow pea color (A) is dominant to green pea color (a). Smooth pea texture (B) is dominant to wrinkled pea texture (b). If pare
nt #1 is homozygous green and heterozygous smooth and parent #2 is homozygous yellow and homozygous wrinkled, what is the probability that the offspring will have yellow, smooth peas? Enter a number 0–100.
1 answer:
Answer:
50%
Explanation:
The genotype of the parent #1 who is homozygous green and heterozygous smooth would be= aaBb and that of the parent #2 who is homozygous yellow and homozygous wrinkled would be=AAbb. A cross between aaBb and AAbb would produce progeny in the following phenotype ratio=
1/2 yellow and smooth: 1/2 yellow and wrinkled.
Therefore, the probability that the offspring will have yellow, smooth peas is 1/2 or 50%
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Answer: There re two different types of phenotypes in the offsprings that is Round yellow and Round green.
Explanation-
As per the Mendelian inheritance, Round shape and yellow color of pea are dominant over wrinkled shape and green color of pea.
According to the question, genotypes of parents are- RrYy ( heterzygous for round and yellow) and RRYy ( homozygous for round and heterozygous for yellow).
The first parent can produce four different gametes that is RY, Ry, rY, ry whereas the second parent will produce only two types of gametes that is RY and Ry.
When they are crossed, they will produce two different phenotypes in the offsprings.
Refer punnett square.
