Answer:
2 to 1
Explanation:
The reaction equation is given as:
2KHCO₃ → K₂CO₃ + CO₂ + H₂O
The conversion factor between the moles of KHCO₃ and K₂CO₃ is 2 to 1.
From the balanced chemical equation, we find out that;
2 moles of 2KHCO₃ will produce 1 mole of K₂CO₃.
So given any mole of either of the reactant or product, we can find the unknown.
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Answer:
Answers are in the explanation.
Explanation:
- The half‑life of A increases as the initial concentration of A decreases. order: <em>2. </em>In the half-life of second-order reactions, the half-life is inversely proportional to initial concentration.
- A three‑fold increase in the initial concentration of A leads to a nine‑fold increase in the initial rate. order: <em>2. </em>The rate law of second-order is: rate = k[A]²
- A three‑fold increase in the initial concentration of A leads to a 1.73‑fold increase in the initial rate. order: <em>1/2. </em>The rate law for this reaction is: rate = k √[A]
- The time required for [A] to decrease from [A]₀ to [A]₀/2 is equal to the time required for [A] to decrease from [A]₀/2 to [A]₀/4. order: <em>1. </em>The concentration-time equation for first-order reaction is: ln[A] = ln[A]₀ - kt. That means the [A] decreasing logarithmically.
- The rate of decrease of [A] is a constant. order: <em>0. </em>The rate law is: rate = k -<em>where k is a constant-</em>
Answer:
You would have 1.96 moles.
Explanation:
You are given 608 grams of calcium phosphate Ca₃(PO₄)₂.
Molar mass (M) is the amount of mass that a substance contains in one mole. This substance can be an element or a compound.
Since the molar mass of the compound Ca₃(PO₄)₂ is 310 g / mole, and taking into account the definition of molar mass, you can apply the following rule of three: if 310 grams of Ca₃(PO₄)₂ are contained in 1 mole, 608 grams of the compound in how many moles are present?
moles= 1.96
<u><em>You would have 1.96 moles.</em></u>
