Answer:
The essence including its given problem is outlined in the following segment on the context..
Explanation:
The given values are:
Moles of CO₂,
x = 0.01962
Moles of water,



Compound's mass,
= 0.4647 g
Let the compound's formula will be:

Combustion's general equation will be:
⇒ 
On putting the estimated values, we get
⇒ 
⇒ 
⇒ 
⇒ 
Now,
x : y : z = 
= 
= 
= 
So that the empirical formula seems to be "C₃H₆O₂".
Mass of water because then it will change his States of matter
Answer:
anyywhere between 20-23 miles
Explanation:
it depends what type of oil field u mean
Answer:
yes
Explanation:
because I think it is correct fo u
Moles of Zn: 26 / 65 = 0.4
Moles of S: 12.8 / 32 = 0.4
Molar ratio of Zn : S = 1 : 1
Empircal formula: ZnS
The answer is C