Answer:
The essence including its given problem is outlined in the following segment on the context..
Explanation:
The given values are:
Moles of CO₂,
x = 0.01962
Moles of water,
Compound's mass,
= 0.4647 g
Let the compound's formula will be:
Combustion's general equation will be:
⇒
On putting the estimated values, we get
⇒
⇒
⇒
⇒
Now,
x : y : z =
=
=
=
So that the empirical formula seems to be "C₃H₆O₂".