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2 years ago

Write the equation of the line given the slope and a point through the line passes

Mathematics

1 answer:

Anuta_ua [19.1K]2 years ago

4 0

Answer:

1.) Y = 5/3 X + 4

2.) Y = 9/4 X - 27/4

Step-by-step explanation:

Given the slope and the coordinate, linear equation of a line can be expressed by using general linear equation. Which is

Y = MX + C

Where the

Slope M = 5/3

Coordinate = (-3,-1) in which

X = -3, Y = -1

Substitute X, Y and M into the general linear equation to achieve C

-1 = 5/3(-3) + C

-1 = - 5 + C

C = 5 - 1

C = 4

Substitute C and M back into the general linear equation.

Therefore, the equation of the line given the slope and a point through the line passes 5/3, and (-3,-1) to be

Y = 5/3 X + 4

2.) Also,

Slope M = 9/4

Coordinate = (3,0) where X = 3, Y = 0

Substitute X, Y and M into the general linear equation to obtain C

0 = 9/4 (3) + C

C = - 27/4

Substitutes C and M back into the general linear equation

Therefore, the equation of the line given the slope and a point through the line passes 9/4 and (3,0)

Y = 9/4 X - 27/4

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PLZ ANSWER ASAP

svetlana [45]

Factor the following:
4 p (4 p - 1) - 3 (4 p - 1)^2

Factor 4 p - 1 from 4 p (4 p - 1) - 3 (4 p - 1)^2:
(4 p - 1) (4 p - 3 (4 p - 1))

-3 (4 p - 1) = 3 - 12 p:
(4 p - 1) (4 p + 3 - 12 p)

Grouping like terms, 4 p - 12 p + 3 = 3 + (4 p - 12 p):
(4 p - 1) (3 + (4 p - 12 p))
4 p - 12 p = -8 p:

Answer: (4 p - 1) (-8 p + 3)

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Factor the following:
m (m + n) - 3 m (m + n)^2

Factor m + n out of m (m + n) - 3 m (m + n)^2, resulting in (m + n) (m - 3 m (m + n)^(2 - 1)):
(m + n) (m - 3 m (m + n)^(2 - 1))

2 - 1 = 1:
(m + n) (m - 3 m (m + n))

Factor m out of m - 3 m (m + n), resulting in m (1 - 3 (m + n)):
m (1 - 3 (m + n)) (m + n)

-3 (m + n) = -3 m - 3 n:
Answer: m (m + n) (-3 m - 3 n + 1)

___________________________________________________________Answer : -(-6 + p^2) (-1 - 6 q + p^2 q)

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Factor the following:
6 u^2 (2 u - 5)^2 - 12 u^2 (2 u - 5) (u + 5)

Factor u^2 out of 6 u^2 (2 u - 5)^2 - 12 u^2 (2 u - 5) (u + 5), resulting in u^2 (6 (2 u - 5)^2 - 12 (2 u - 5) (u + 5)):
u^2 (6 (2 u - 5)^2 - 12 (2 u - 5) (u + 5))

(2 u - 5) (2 u - 5) = (2 u) (2 u) + (2 u) (-5) + (-5) (2 u) + (-5) (-5) = 4 u^2 - 10 u - 10 u + 25 = 4 u^2 - 20 u + 25:
u^2 (6 4 u^2 - 20 u + 25 - 12 (2 u - 5) (u + 5))

6 (4 u^2 - 20 u + 25) = 24 u^2 - 120 u + 150:
u^2 (24 u^2 - 120 u + 150 - 12 (2 u - 5) (u + 5))

(u + 5) (2 u - 5) = (u) (2 u) + (u) (-5) + (5) (2 u) + (5) (-5) = 2 u^2 - 5 u + 10 u - 25 = 2 u^2 + 5 u - 25:u^2 (150 - 120 u + 24 u^2 - 122 u^2 + 5 u - 25)

-12 (2 u^2 + 5 u - 25) = -24 u^2 - 60 u + 300:
u^2 (-24 u^2 - 60 u + 300 + 24 u^2 - 120 u + 150)

Grouping like terms, 24 u^2 - 24 u^2 - 60 u - 120 u + 150 + 300 = (-120 u - 60 u) + (24 u^2 - 24 u^2) + (150 + 300):
u^2 ((-120 u - 60 u) + (24 u^2 - 24 u^2) + (150 + 300))

-120 u - 60 u = -180 u:
u^2 (-180 u + (24 u^2 - 24 u^2) + (150 + 300))
150 + 300 = 450:
u^2 (-180 u + (24 u^2 - 24 u^2) + 450)

24 u^2 - 24 u^2 = 0:
u^2 (450 - 180 u)

Factor 90 out of 450 - 180 u:
Answer: u^2×90 (5 - 2 u)

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3 years ago

(4n⁴-8n+4) - (8n²+4n⁴+1) How do I simplify this expression?

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Answer:

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Step-by-step explanation:

you combine the like terms

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3 years ago

Evaluate 6n-2 for n=4.

kvasek [131]

Answer:

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Step-by-step explanation:

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3 years ago

Twenty-seven is % of 60 help mee asap

jok3333 [9.3K]

Answer: The answer is: " 45 % " .

________________________________________________

→ " Twenty-seven is 45 % of 60. "

________________________________________________

Step-by-step explanation:

________________________________________________

The question asks:

" 27 is what % {percentage] of 60 " ? ;

________________________

So: " 27 = (n/100) * 60 " ; Solve for "n" ;

________________________________________________

Method 1:

________________________________________________

→ (n/100) * 60 = 27 ;

Divide each side by 60 :

→ [ (n/100) * 60 ] / 60 = 27 /60 ;

to get:

→ (n/100) = 27/60 ;

Now: Cross-factor multiply:

→ 60n = (27)*(100) ;

to get:

→ 60n = 2700 ;

Divide each side by "60" ;

→ 60n = 2700/ 60 ;

to get: n = 45 ;

________________________

→ The answer is: 45 % .

→ " Twenty-seven is 45 % of 60."

________________________________________________

Method 2:

________________________________________________

The question asks:

" 27 is what % {percentage] of 60 " ?

________________________

To solve this problem:

Rephrase this question as:

________________________

" 27 is 60% of what number ? "

→ The answer will be the same!

________________________

→ 27 = (60/100)* n ; Solve for "n" ;

Multiply each side of the equation by "100" ; to eliminate the fraction:

→ 100 * 27 = 100 * [ (60/100)* n ] ;

to get:

→ 2700 = 60n ;

↔ 60n = 2700 ;

Divide Each Side of the equation by "60" ;

→ 60n/60 = 2700 / 60 ;

to get: n = 45 ;

________________________________________________

→ The answer is: 45 % .

→ " Twenty-seven is 45 % of 60."

________________________________________________

Method 2: Variant 1 of 2:

________________________________________________

When we have:

→ 27 = (60/100)* n ; Solve for "n" ;

________________________

Note that: "(60/100) = (60÷ 100) = (6 ÷ 10)" ; since: in "(60/100)" ; the "zero" from the "numerator" cancels out; And: the "last zero" in "100" — from the "denominator" cancels out; since we are dividing "each side" of the fraction by "10" ;

→ "(60÷10) / (600÷10)" = " 6/10 " ;

→ " (6/10)" ; that is; "six-tenths"} ;

→ can be represented by: " 0.6 " ;

→ {by convention; but specifically, here is the explanation} — as follows:

________________________

→ "(6/10)" = " (6 ÷ 10) " ;

Note: When dividing a number by "10" ; we take the original number; and move the decimal point to the left; & then we rewrite that number as the "answer".

Note: When multiplying or dividing by a positive, non-zero integer factor of "10" that has at least 1 (one) "zero" after that particular factor of "10". We can get the answer by taking the original number & moving the decimal point the number of spaces as designated by the number of zeros following the particular [aforementioned factor of "10".].

We move the decimal point to the right if we are multiplying; and to the left if we are dividing. In this case, we are dividing "6" by "10 " :

→ " 6 ÷ 10 = ? " ;

→ " 6. ÷ 10 = ? " ;

We take the: " 6. " ; and move the decimal point "one space backward [i.e. "to the left"]; since we are dividing by "10" ;

→ to get: " .6 " ; & we rewrite this value as "0.6" in a rewritten equation:

________________________

So; we take our equation:

→ 27 = (60/100)*n ; And rewrite—substituting "0.6" for

"(60/100)"— as follows:

________________________

→ 27 = (0.6)n ; ↔ (0.6) n = 27 ;

Multiply each side of the equation by "10" ; to eliminate the decimal:

→ 10 * [ (0.6)n ] = 27 * 10 ;

to get:

→ 6n = 270 ;

Divide each side of the equation by "6" ; to isolate "n" on one side of the equation; & to solve for "n" ;

→ 6n / 6 = 270 / 6 ;

to get: n = 45 ;

________________________________________________

→ The answer is: 45 % .

→ " Twenty-seven is 45 % of 60."

________________________________________________

Method 2 (variant 2 of 2):

________________________________________________

We have the equation: 27 = (60/100)* n ; Solve for "n" ;

________________________

Note: From Method 2 (variant) 1 of 2— see above):

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Note: Refer to the point at which we have:

________________________

→ " { (60÷10) / (600÷10)" = " (6/10) " ; that is; "six-tenths"} ;

________________________

Note that the fraction— "(6/10)" ; can be further simplified:

→ "(6/10)" = "(6÷2) / (10÷2)" = "(3/5)" ;

Now, we can rewrite the equation;

→ We replace "(60/100)" ; with: "(3/5)" :

→ 27 = (3/5)* n ; Solve for "n" ;

↔ (3/5)* n = 27 ;

↔ (3n/5) = 27 ;

Multiply Each Side of the equation by "5" ;

→ 5* (3n/5) = 27 * 5 ;

to get:

→ 3n = 135 ;

Divide Each side of the equation by "3" ; to isolate "n" on one side of the equation; & to solve for "n" ;

→ 3n / 3 = 135 / 3 ;

to get: n = 45 ;

________________________________________________

→ The answer is: 45 % .

→ " Twenty-seven is 45 % of 60."

________________________________________________

Hope this answer is helpful!

Wishing you the best in your academic endeavors

— and within the "Brainly" community!

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7 0

3 years ago

Read 2 more answers

What is 975, 462 round to the nearest hundred thousand

podryga [215]

Answer:

it would be 1 million, ( 1,000,000 )

Step-by-step explanation:

1.) look to the right of the nine , (7)

2.) 7 is greater than five therefore rounding it up to 1,000,000

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3 years ago