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inessss [21]
3 years ago
8

Thirty five percent of the employees in a company have managerial positions, and 67 percent of the employees in the company have

MBA degrees. Also, 53 percent of the managers have MBA degrees. Using the probability formulas, find the proportion of employees who either have MBAs or are managers.
Mathematics
1 answer:
seraphim [82]3 years ago
7 0

Answer:

49% of employees who either have MBA or are managers.

Step-by-step explanation:

We are given the following information in the question:

P(Managerial) = 35% = 0.035

P(MBA) = 67% = 0.67

P(\text{Managerial} \cap \text{MBA}) = 53\% = 0.53

We have to find the probability of employees who either are have MBA or are managers.

According to De-Morgan's law:

P(\text{Managerial} \cup \text{MBA}) = P(\text{Managerial}) + P(\text{MBA}) - P(\text{Managerial} \cap \text{MBA}) \\P(\text{Managerial} \cup \text{MBA}) = 0.35 + 0.67 - 0.53 = 0.49

Thus, around 49% of employees who either have MBA or are managers.

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The radius of a sphere is 6cm. What is the volume of the sphere? (As pi)
natita [175]

Answer:

288πcm^3

Step-by-step explanation

v=(4/3)πr^3

v=(4/3)π*6^3

v=288πcm^3

4 0
3 years ago
Can I get the answer
timama [110]
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6 0
3 years ago
Explain how you get 608,149 to the nearest thousand place
Hitman42 [59]

Answer:

Step-by-step explanation:

608,000

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7 0
3 years ago
Can somebody please help me with this problem
Licemer1 [7]

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To solve, simply follow the way of finding the volume of a cylinder.

Calculate volume of a cylinder: V = πr2h.

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5 0
3 years ago
A ship from Port travels fot 60km on the bearing of 129°.It continues to travel and changes direction for another 50km on a bear
Eddi Din [679]

Answer:

The ship is approximately 100 km to the Port.

Step-by-step explanation:

The sketch to the question gives a triangle with two sides and an included angle. Let the distance from the Port to the stopping point of the ship be represented by c. It can be determined by the application of cosine rule. Cosine rule states that:

c^{2} = a^{2} + b^{2} -2ab Cos C

a = 50 km

b = 60 km

C = 51 + 80 = 131^{o}

So that;

c^{2} = 50^{2} + 60^{2} -2(50 x 60) Cos 131^{o}

   = 2500 + 3600 -6000 x -0.6561

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c^{2} = 10036.6

c = \sqrt{10036.6}

  = 100.183

c = 100.18 km

Thus, the ship is approximately 100 km to the Port.

5 0
3 years ago
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