Answer:
- 20 + 8i
Step-by-step explanation:
Noting that i² = - 1
Given
[(6i + 9) + (4i - 5)] × 2i ← evaluate the terms inside the square bracket
= ( 6i + 9 + 4i - 5 ) × 2i
= (10i + 4) × 2i ← multiply each term in the parenthesis by 2i
= 20i² + 8i
= 20(- 1) + 8i
= - 20 + 8i
Answer:
The percent of callers are 37.21 who are on hold.
Step-by-step explanation:
Given:
A normally distributed data.
Mean of the data,
= 5.5 mins
Standard deviation,
= 0.4 mins
We have to find the callers percentage who are on hold between 5.4 and 5.8 mins.
Lets find z-score on each raw score.
⇒
...raw score,
=
⇒ Plugging the values.
⇒
⇒
For raw score 5.5 the z score is.
⇒
⇒
Now we have to look upon the values from Z score table and arrange them in probability terms then convert it into percentages.
We have to work with P(5.4<z<5.8).
⇒ 
⇒ 
⇒
⇒
and
.<em>..from z -score table.</em>
⇒ 
⇒
To find the percentage we have to multiply with 100.
⇒ 
⇒
%
The percent of callers who are on hold between 5.4 minutes to 5.8 minutes is 37.21
The 3rd one is the right one!!!!!!!!!!!!!!!!!!
50 divided by 8 = 6.25
1oz perfume = $6.25
110 divided by 17 = 6.4705
1oz perfume = $6.4705
Therefore the second option is cheaper