E = Energy m = Mass c = Speed of light.
Yhuihoifjhh <span>F = Gm1m2 / r^2
if the masses are doubled then the force is increased by a factor of 4
if the distance is doubled the force is decreased by a factor of 1/ 2^2
the net result is no change in force</span>
Comment
The only reason you can do this is that the charges are the same. If they were not, the problem would not be possible.
Equation
The field equation is, in its simplest form,
E = kq/r^2
So each of the charges are pulling / pushing in the same direction. The equation becomes.
kq/r^2 - (-kq/r^2) = Field magnitude in N/C
Givens
- K = 9 * 10^9 N m^2 / c^2
- E = 45 N/C
- r = 7.5/2 = 3.75 cm * ( 1 m / 100 cm) = 0.0375 m
- Find Q
Solution
k*q/0.0375 ^2 - (-kq/0.0375^2) = 45 N/C Combine
2*k*q / 0.0375^2 = 45 N/C Divide by 2
kq /(0.0375^2) = 22.5 N/C Multiply by 0.0375^2
kq = 22.5 * 0.0375 ^2 Find d^2
kq = 22.5 * 0.001406 Combine
kq = 0.03164 N/C * m^2 Divide by k
q = 0.03164 N * m^2 /C / 9*10^9 N m^2 / c^2
q = 2.84760 * 10 ^8 C
I've left the cancellation of the units for you. Notice that only 1 C is left and it is in the numerator as it should be.
Answer:
Considering that there is no obstructions, he could go west from the start.
Explanation:
