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sattari [20]
2 years ago
13

JUST PLZ HELP!!! Why does the lightbulb in the right electrical circuit turn on but not the one on the left?

Physics
2 answers:
makkiz [27]2 years ago
8 0
Because,

In left image pin is not touch to the wire.

In right image pin is touch to the wire.

Hope it helps you.....

Plz...Plz...Plz...Plz…Plz…

Mark be Brainliest.....

Please.....

And..

Please thanks me.....

Plz.....Plz.....
tekilochka [14]2 years ago
4 0

In the open circuit the current cannot flow from one end of the power source to the other. Because of this there is no current flow, and therefore the light does not turn on.

*This is not my answer*

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A transformer is designed to provide 6 V from a 150 V supply. If the primary coil has 1000 turns, how many turns does the second
zavuch27 [327]
The applicable relationship is N1/N2 = V1/V2, meaning the ratio of primary voltage to secondary voltage is equal to the ratio of primary turns to secondary turns.

Here N1 = 1000, V1 = 250, V2 = 400V and N2 = TBD.

Rewriting the above relationship, N2 = N1 V2/V1 = 1000 x 400/250 = 1600 turns.
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2 years ago
A driver of a car enters a new 110 km/h speed zone on the highway. The driver begins to accelerate immediately and reaches 110 k
levacccp [35]

Answer:

30Km/h

Explanation:

acceleration is the change of speed in a given time so when we substract the accelerations we can know how much the car goes per an hour

3 0
2 years ago
What is the special name for doctors who deal with cancer?
Sladkaya [172]
Oncology is the study of cancer, so the doctors are called oncologists
8 0
3 years ago
Read 2 more answers
To practice Problem-Solving Strategy 17.1 for wave interference problems. Two loudspeakers are placed side by side a distance d
Nimfa-mama [501]

Complete Question

The compete question is shown on the first uploaded question

Answer:

The speed is  v  =  350 \  m/s  

Explanation:

From the question we are told that

   The  distance of separation is  d =  4.00 m  

  The distance of the listener to the center between the speakers is  I =  5.00 m

  The change in the distance of the speaker is by k  =  60 cm  =  0.6 \  m

    The frequency of both speakers is f =  700 \  Hz

Generally the distance of the listener to the first speaker is mathematically represented as

       L_1  =  \sqrt{l^2 + [\frac{d}{2} ]^2}

       L_1  =  \sqrt{5^2 + [\frac{4}{2} ]^2}

        L_1  =   5.39 \  m

Generally the distance of the listener to second speaker at its new position is  

          L_2  =  \sqrt{l^2 + [\frac{d}{2} ]^2 + k}

       L_2  =  \sqrt{5^2 + [\frac{4}{2} ]^2 + 0.6}

        L_2  =   5.64  \  m  

Generally the path difference between the speakers is mathematically represented as

        pD  = L_2 - L_1  =  \frac{n  *  \lambda}{2}

Here \lambda is the wavelength which is mathematically represented as

         \lambda =  \frac{v}{f}

=>    L_2 - L_1  =  \frac{n  *  \frac{v}{f}}{2}

=>    L_2 - L_1  =  \frac{n  *  v}{2f}  

=>    L_2 - L_1  =  \frac{n  *  v}{2f}  

Here n is the order of the maxima with  value of  n =  1  this because we are considering two adjacent waves

=>    5.64 - 5.39   =  \frac{1  *  v}{2*700}      

=>    v  =  350 \  m/s  

7 0
3 years ago
Please help I need this fast
Ghella [55]
The solution has reacted.
5 0
3 years ago
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