Answer:
Explanation:
The only thing I can figure you need here is the accleration of the sled. The equation we need to find this is Newton's Second Law that says that sum of the forces acting on an object is equal to the object's mass times its acceleration. For us, that looks like this because of the friction working against the sled:
F - f = ma but of course it's much more involved than that simple equation! We have the F value as 230 N, and we have the mass as 105, but we do not have the frictional force, f, and we need it to solve for a in the above equation. We know that
f = μ
where μ is the coefficient of friction, and
is the normal force, aka weight of the object. We will use the coefficient of friction and find the weight in order to fill in for f:
so
so the weight of the sled is
1.0 × 10³ with the correct number of sig dig there. Now to find f:
f = (.025)(1.0 × 10³) so
f = 25 to the correct number of sig fig. Now on to our "real" equation:
F - f = ma and
230 - 25 = 105a. We have to do the subtraction first, round, and then divide since the rules for addition and subtraction are different from the rules for dividing and multiplying.
230 - 25 will round to the tens place giving us 210. Then
210 = 105a. 210 has 2 sig figs in it while 105 has 3, so we will divide and round to 2 sig fig:
a = 2.0 m/sec²
The total momentum of the system is 2.14i + 21.27j.
A vector quantity with both direction and magnitude is momentum. Kg m/s (kilogram meter per second) or N s serve as its units (newton second).
The total starting momentum of a system must match the entire final momentum of the system since momentum is a conserved quantity. The overall momentum does not change.
The total momentum of the system is defined as follows:
As momentum is vector quantity and vectors can be added, so, the momentum of a system is given by
P = Pₓ + P'
where Pₓ is the x-component of momentum
P' is the y-component of the momentum
Also, we know that
P=mv
where m is mass
v is velocity
Thus,
P = Pₓ + P'
P = m₁vₓ + m₂v'
vₓ is the x-component of the velocity
v' is the y- component of the velocity
Given, m₁= 3.2kg
m₂ = 2.9kg
Now,
P = 3.2 (2.3i + 4.2j) + 2.9 (-1.8i +2.7j)
P = (7.36i + 13.44j) + (-5.22i + 7.83j)
P = 2.14i + 21.27j
Thus, the total momentum of the given system is 2.14i + 21.27j.
Learn more about the momentum here:
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U=RI Ohm's law
then R=U/I
=120/0.08
=2250Ω
hope this helps you
Answer:
<u><em>0.03 m/s</em></u>
Explanation:
<em>Applying law of conservation of momentum, </em>
- <em>m₁v₁ + m₂v₂ = (m₁ + m₂)v</em>
- <em>0.105(24) + 75(0) = (0.105 + 75)v</em>
- <em>75.105v = 2.52</em>
- <em>v = 2.52/75.105</em>
- <em>v = </em><u><em>0.03 m/s</em></u>
The final volume of the gas is 144.25 L
Explanation:
For an ideal gas kept at constant pressure, the work done by the gas on the surroundings is given by

where
p is the pressure of the gas
is the initial volume
is the final volume
For the gas in the cylinder in this problem,
p = 2.00 atm

And we also know the work done,
W = 288 J
So we can solve the equation for
, the final volume:

Learn more about ideal gases:
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