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OverLord2011 [107]
4 years ago
11

Solve the inqualities 3x-3<9

Mathematics
1 answer:
pentagon [3]4 years ago
8 0

Answer: x < 4

Step-by-step explanation: When solving the inequality 3x - 3 < 9, just like an equation our first step is to isolate the <em>x</em> term which is 3x by adding 3 to both sides of the inequality.

On the left, -3 + 3 cancels and we have 3x.

Make sure to bring down the < sign.

On the right, 9 + 3 simplifies to 12.

So we have 3x < 12.

Now, divide both sides of the inequality by 3 to isolate <em>x</em>.

When we do that we get <em>x < 4</em>

So our answer is x < 4.

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The hypotenuse of a right triangle measures 10 inches and the side opposite to &lt;0 one of the non right angles is 5 inches lon
AfilCa [17]
Sin = Opposite/ Hypotenuse
Sin (theta)= 5/10
Sin^-1(5/10)=30
theta=30
5 0
3 years ago
6)Factor: x^2+1/3x+1/36
trasher [3.6K]

Answer:

(x+4)(x+9)=0. Your answer would be x=-4 and x=-9. Explanation:: (x+4)(x+9) x times x=x2 x(9)+x(4)=13x 4 times 9=36 = x2+13x+36.(x+4)(x+9)=0. Your answer would be x=-4 and x=-9. Explanation:: (x+4)(x+9) x times x=x2 x(9)+x(4)=13x 4 times 9=36 = x2+13x+36.

7 0
3 years ago
HELP PLEASE!! THANK YOU!
dmitriy555 [2]

Answer: choice B, 40.5 degrees

The triangle is isosceles based on the fact that AC = BC (the tick marks are the same). The angles opposite the congruent sides are also congruent

angle A = angle B = x for some unknown number x

The three angles A,B,C add to 180, so,

A+B+C = 180

x+x+99 = 180

2x+99 = 180

2x = 180-99

2x = 81

x = 81/2

x = 40.5

So angle A and angle B are both 40.5 degrees

Check:

A+B+C = 180

40.5+40.5+99 = 180

180 = 180 answer is confirmed

==============================

Edit

The sides with the two tick marks are the same length, so 7x-4 is the same as length as 31

7x-4 = 31

7x = 31+4

7x = 35

x = 35/7

x = 5

Answer is choice B) 5

3 0
4 years ago
Find all intervals on which the graph of f(x)=(x-1)/(x+3) is concave upward
Yuliya22 [10]
To find concavity we need to find the second derivative.
Use quotient rule to find f'(x)=4/(x+3)^2
Then use chain rule to find f''(x)=-8/(x+3)^3
To find potential inflection points, we need to find all x values where the second derivative is equal to 0 or is undefined.

Set the numerator and denominator equal to 0 and solve.

(x+3)^3=0
x+3=0
x= -3

Now plug a value less than -3 and greater than -3 into the second derivative to find where the concavity is upward (positive number).

Since f''(-4) is positive, that means that f(x) is concave up on the interval (-infinity, -3).




4 0
4 years ago
Find the EXACT area AND circumference of the following circle.
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There is no picture so I can't help.

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