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Mrac [35]
3 years ago
15

Two forces with magnitudes of 100 and 50 pounds act on an object at angles of 50° and 160°, respectively. Find the direction and

magnitude of the resultant force
Mathematics
1 answer:
VikaD [51]3 years ago
6 0
The resultant force is the sum of all forces positioned at different directions and placed in a specific angle. In this case, we can take the short way to answer this problem. we use the calculator and shift the mode to complex to add 100<50 and 50<160. the answer is 95.29<79.54. The magnitude is 95.29 pounds and the angle is 79.54<span>°.</span>
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A group of 4 people go out to eat. They split the bill so that each person pays 1/4 of the total price appetizers is $6 main dis
postnew [5]

Answer:

(6 + 9) / 4

Step-by-step explanation: you have to add the costs of the appetizers and the main dish ( 6 + 9 ). then you have to divide the sum by 4 since there are 4 people in total ( /4 ).

3 0
3 years ago
Determine whether the value is from a discrete or continuous data set. Number of coins in a jar is 78 number of coins in a jar i
Phoenix [80]

Determine whether the value is from a discrete or continuous data set. Number of coins in a jar is 78 number of coins in a jar is 78

Answer: Number of coins in a jar is from a discrete data set. Because the given variable is countable in a finite amount of time.

If a variable can take on any value between two specified values, it is called a continuous variable; otherwise, it is called a discrete variable.


3 0
3 years ago
Find value of p in..6p-1/3(p+1)=8(p+1/32​
puteri [66]

The answer is,

p =  -  \frac{1}{4}

6 0
3 years ago
If you have 2 pounds of grapes and there $6 how much is 1 pound grapes?
Vikki [24]

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Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
If X²⁰¹³ + 1/X²⁰¹³ = 2, then find the value of X²⁰²² + 1/X²⁰²² = ?​
enyata [817]

Step-by-step explanation:

\bf➤ \underline{Given-} \\

\sf{x^{2013} + \frac{1}{x^{2013}} = 2}\\

\bf➤ \underline{To\: find-} \\

\sf {the\: value \: of \: x^{2022} + \frac{1}{x^{2022}}= ?}\\

\bf ➤\underline{Solution-} \\

<u>Let us assume that:</u>

\rm: \longmapsto u =  {x}^{2013}

<u>Therefore, the equation becomes:</u>

\rm: \longmapsto u +  \dfrac{1}{u}  = 2

\rm: \longmapsto \dfrac{  {u}^{2} + 1}{u}  = 2

\rm: \longmapsto{u}^{2} + 1 = 2u

\rm: \longmapsto{u}^{2} - 2u + 1 =0

\rm: \longmapsto  {(u - 1)}^{2} =0

\rm: \longmapsto u = 1

<u>Now substitute the value of u. We get:</u>

\rm: \longmapsto {x}^{2013}  = 1

\rm: \longmapsto x = 1

<u>Therefore:</u>

\rm: \longmapsto {x}^{2022}  +  \dfrac{1}{ {x}^{2022} }  = 1 + 1

\rm: \longmapsto {x}^{2022}  +  \dfrac{1}{ {x}^{2022} }  = 2

★ <u>Which is our required answer.</u>

\textsf{\large{\underline{More To Know}:}}

(a + b)² = a² + 2ab + b²

(a - b)² = a² - 2ab + b²

a² - b² = (a + b)(a - b)

(a + b)³ = a³ + 3ab(a + b) + b³

(a - b)³ = a³ - 3ab(a - b) - b³

a³ + b³ = (a + b)(a² - ab + b²)

a³ - b³ = (a - b)(a² + ab + b²)

(x + a)(x + b) = x² + (a + b)x + ab

(x + a)(x - b) = x² + (a - b)x - ab

(x - a)(x + b) = x² - (a - b)x - ab

(x - a)(x - b) = x² - (a + b)x + ab

6 0
3 years ago
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