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Varvara68 [4.7K]
3 years ago
14

Which statement best describes the difference between how mirrors and lenses interact with light?

Physics
2 answers:
evablogger [386]3 years ago
8 0

Explanation :

Mirrors are made up of silver coated glass. The mirrors used to focus an image at a point. It can be of any type like a plane mirror, concave mirror and the convex mirror.

Mirrors follow the law of reflection. The law states that :

  • The angle of incidence is equal to the angle of reflection.
  • The incident ray, reflected ray and the normal all lie in the same plane.

A lens is used to refract light. The amount of refraction depends on the type of material and its shape. It can be of two types i.e. convex and concave lens.

So, the correct option is (B) "Mirrors form images by reflecting light; lenses do not".

IceJOKER [234]3 years ago
5 0
The answer is B on APEX
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HACTEHA [7]

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2 years ago
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Someone help me haha;(
Nikitich [7]

Answer: vf = 51 m/s

d = 112 m

Explanation: Solution attached:

To find vf we use acceleration equation:

a = vf - vi / t

Derive to find vf

vf = at + vi

Substitute the values

vf = 3.5 m/s² ( 8.0 s) + 23 m/s

= 51 m/s

To solve for distance we use

d = (∆v)² / 2a

= (51 m/s - 23 m/s )² / 2 ( 3.5 m/s²)

= (28 m/s)² / 7 m/s²

= 784 m/s / 7 m/s²

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6 0
2 years ago
In 2000, NASA placed a satellite in orbit around an asteroid. Consider a spherical asteroid with a mass of 1.40×1016 kg and a ra
Arturiano [62]

A) 8.11 m/s

For a satellite orbiting around an asteroid, the centripetal force is provided by the gravitational attraction between the satellite and the asteroid:

m\frac{v^2}{(R+h)}=\frac{GMm}{(R+h)^2}

where

m is the satellite's mass

v is the speed

R is the radius of the asteroide

h is the altitude of the satellite

G is the gravitational constant

M is the mass of the asteroid

Solving the equation for v, we find

v=\sqrt{\frac{GM}{R+h}}

where:

G=6.67\cdot 10^{-11} m^3 kg^{-1}s^{-2}

M=1.40\cdot 10^{16}kg

R=8.20 km=8200 m

h=6.00 km = 6000 m

Substituting into the formula,

v=\sqrt{\frac{(6.67\cdot 10^{-11})(1.40\cdot 10^{16}kg)}{8200 m+6000 m}}=8.11 m/s

B) 11.47 m/s

The escape speed of an object from the surface of a planet/asteroid is given by

v=\sqrt{\frac{2GM}{R+h}}

where:

G=6.67\cdot 10^{-11} m^3 kg^{-1}s^{-2}

M=1.40\cdot 10^{16}kg

R=8.20 km=8200 m

h=6.00 km = 6000 m

Substituting into the formula, we find:

v=\sqrt{\frac{2(6.67\cdot 10^{-11})(1.40\cdot 10^{16}kg)}{8200 m+6000 m}}=11.47 m/s

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3 years ago
A long solenoid has a radius of 2.0 cm and has 700 turns/m. If the current in the solenoid is decreasing at the rate of 8.0 A/s,
Brrunno [24]

Answer:

The magnitude of the induced electric field at a point 2.5 cm from the axis of the solenoid is 8.8 x 10⁻⁵ V/m

Explanation:

given information:

radius, r = 2.0 cm

N = 700 turns/m

decreasing rate, dI/dt = 9.0 A/s

the magnitude of the induced electric field at a point 2.5 cm (r = 2.5 cm = 0.025 m) from the axis of the solenoid?

the magnetic field at the center of solenoid

B = μ₀nI

where

B = magnetic field (T)

μ₀ = permeability (1.26× 10⁻⁶ T.m/A)

n = the number turn per unit length (turn/m)

I = current (A)

dB/dt = μ₀n dI/dt                                           (1)

now we calculate the induced electric field by using

E = \frac{1}{2}r\frac{dB}{dt}  

\frac{dB}{dt} = 2E/r                                                     (2)

where

E = the induced electric field (V/m)

we substitute the firs and second equation, thus

dB/dt = μ₀n dI/dt  

2E/r = μ₀n dI/dt  

E = (1/2) r μ₀n dI/dt

  = (1/2) (0.025) (1.26× 10⁻⁶) (700) (8)

  = 8.8 x 10⁻⁵ V/m

6 0
3 years ago
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