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tensa zangetsu [6.8K]
3 years ago
9

What is the formula for calculating the efficiency of a heat engine

Physics
1 answer:
horsena [70]3 years ago
5 0
The answer is Eficiency=T<< Tox100
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What temperature is required to transfer waste heat to the environment for a heat engine to be 100 percent efficient?
OLEGan [10]
This can be seen as a trick question because heat engines can typically never be 100 percent efficient. This is due to the presence of inefficiencies such as friction and heat loss to the environment. Even the best heat engines can only go up to around 50% efficiency.
6 0
3 years ago
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Why might it be necessary to ignore some of the data points just before and just after the collision?
krek1111 [17]
We have no idea. We need to examine the experimental set-up. You've given us no information, except that there may have been some sort of collision.
7 0
3 years ago
Which of the following is occurring while a satellite is in orbit around Earth? O It is continuously pulling away from Earth It
hoa [83]

AnswerIt is continuously falling towards the surface of the earth

Explanation:

since gravity from earth is the thing that keeps it constantly in orbit

4 0
3 years ago
An x-ray beam with wavelength 0.240 nmnm is directed at a crystal. As the angle of incidence increases, you observe the first st
siniylev [52]

Answer:

The spacing between the planes of the crystal is 0.295 nm

Explanation:

Given:

λ = wavelength = 0.24 nm

θ = angle of incidence = 66°

The spacing d between the planes of the crystal is equal:

d=\frac{n\lambda }{2cos\theta } =\frac{1*0.24}{2*cos66} =0.295nm

7 0
2 years ago
What is the maximum height achieved if a 0.600 kg mass is thrown straight upward with an initial speed of 75.0 m·sâ1? ignore th
loris [4]

We can solve the problem by using the law of conservation of energy:

- at the beginning, all mechanical energy of the object is just kinetic energy: K=\frac{1}{2}mv^2, where m is the mass and v is the velocity

- at the point of maximum height, all mechanical energy of the object is just gravitational potential energy: U=mgh, where h is the maximum height

Therefore, the conservation of energy becomes:

\frac{1}{2}mv^2 = mgh

Re-arranging, we find the maximum height:

h=\frac{v^2}{2g} = \frac{(75.0 m/s)^2}{2(9.8 m/s^2)}=287.0 m


6 0
3 years ago
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