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s344n2d4d5 [400]
3 years ago
6

Which of the following would decrease the resistance in a wire?

Physics
2 answers:
Anarel [89]3 years ago
8 0
The last one I believe
Alina [70]3 years ago
5 0

Answer:

Increase the thickness of the wire

Explanation:

From:

https://www.bbc.co.uk/bitesize/guides/z9sb2p3/revision/3

The resistance in a wire increases as:

the length of the wire increases

the thickness of the wire decreases

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Granite is uplifted by the movement of tectonic plates. It will most likely become _____.
hammer [34]
<h3><u>Answer;</u></h3>

Sedimentary rock

Granite is uplifted by the movement of tectonic plates. It will most likely become a <em><u>sedimentary rock</u></em>.

<h3><u>Explanation</u>;</h3>
  • Granite is an intrusive igneous rock that is coarse-grained and light-colored, mainly composed of feldspar and quartz.  It forms from the crystallization or the cooling of magma in the Earth's crust.
  • <em><u>When igneous rocks such as granite undergo weathering and erosion they form sediments that are deposited, then compacted and cemented by the movement of tectonic plates resulting to the formation of sedimentary rocks.</u></em>
8 0
3 years ago
What is the momentum of a 200 kg car traveling 30 m/s to the right?
hichkok12 [17]
Momentum=mass × velocity
momentum= 200×30
=6000kgm/s
8 0
4 years ago
A 3.00-kg block starts from rest at the top of a 33.0° incline and slides 2.00 m down the incline in 1.80 s. (a) Find the accele
ElenaW [278]

(a) 1.23 m/s^2

Let's analyze the motion along the direction of the incline. We have:

- distance covered: d = 2.00 m

- time taken: t = 1.80 s

- initial velocity: u = 0

- acceleration: a

We can use the following SUVAT equation:

d = ut + \frac{1}{2}at^2

Since u=0 (the block starts from rest), it becomes

d=\frac{1}{2}at^2

So by solving the equation for a, we find the acceleration:

a=\frac{2d}{t^2}=\frac{2(2.00 m)}{(1.80 s)^2}=1.23 m/s^2

(b) 0.50

There are two forces acting on the block along the direction of the incline:

- The component of the weight parallel to the surface of the incline:

W_p = mg sin \theta

where

m = 3.00 kg is the mass of the block

g = 9.8 m/s^2 is the acceleration due to gravity

\theta=33.0^{\circ} is the angle of the incline

This force is directed down along the slope

- The frictional force, given by

F_f = - \mu mg cos \theta

where

\mu is the coefficient of kinetic friction

According to Newton's second law, the resultant of the forces is equal to the product between mass and acceleration:

W-F_f = ma\\mg sin \theta - \mu mg cos \theta = ma

Solving for \mu, we find

\mu = \frac{g sin \theta - a}{g cos \theta}=\frac{(9.8 m/s^2)sin 33.0^{\circ} - 1.23 m/s^2}{(9.8 m/s^2) cos 33.0^{\circ}}=0.50

(c) 12.3 N

The frictional force acting on the block is given by

F_f = \mu mg cos \theta

where

\mu = 0.50 is the coefficient of kinetic friction

m = 3.00 kg is the mass of the block

g = 9.8 m/s^2 is the acceleration of gravity

\theta=33.0^{\circ} is the angle of the incline

Substituting, we find

F_f = (0.50)(3.00 kg)(9.8 m/s^2) cos 33.0^{\circ} =12.3 N

(d) 6.26 m/s

The motion along the surface of the incline is an accelerated motion, so we can use the following SUVAT equation

v^2 - u^2 = 2ad

where

v is the final speed of the block

u = 0 is the initial speed

a = 1.23 m/s^2 is the acceleration

d = 2.00 m is the distance covered

Solving the equation for v, we find the speed of the block after 2.00 m:

v=\sqrt{u^2 + 2ad}=\sqrt{0^2+2(9.8 m/s^2)(2.00 m)}=6.26 m/s

5 0
3 years ago
What is the net force when forces applied are 300 N to the right and 100 N to the right
labwork [276]

Answer:

400 Newtons to the right.

Explanation:

You have 300 Newtons that are being applied to the right and you also 100 Newtons to the right. When calculating net force with the forces that go the same direction, you add them. 300 plus 100 is 400. Therefore, it is 400 Newtons or N to the right. Hope this helps!

8 0
3 years ago
Bohr analyzed the spectral lines of hydrogen.<br><br>true or false?​
trasher [3.6K]

Answer:

I think it is false. Johann balmer analyzed the spectral lines of hydrogen

6 0
3 years ago
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