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Leona [35]
3 years ago
14

Does the frequency distribution appear to have a normal distribution using a strict interpretation of the relevant​ criteria? Te

mperature ​(degrees​F) Frequency 50 dash 54 2 55 dash 59 0 60 dash 64 4 65 dash 69 12 Temperature ​(degrees​F) Frequency 70 dash 74 7 75 dash 79 5 80 dash 84 1 Does the frequency distribution appear to have a normal​ distribution?

Physics
1 answer:
lukranit [14]3 years ago
4 0

Answer:

And as we can see on the plot we have the distribution left skewed so then this distribution is not normal because we don't have a bell shaped histofram and is not symmetric.

Explanation:

Assuming the following dataset

Temperature (F)       Frequency

50-54                          2

55-59                          0

60-64                          4

65-69                          12

70-74                           7

75-79                           5

80-84                           1

For this case we can construct the histogram with the following R code.

f<-c(2,0,4,12,7,5,1)

> barplot(f)

And the result is on the figure attached.

And as we can see on the plot we have the distribution left skewed so then this distribution is not normal because we don't have a bell shaped histofram and is not symmetric.

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"On a movie set, an alien spacecraft is to be lifted to a height of 32.0 m for use in a scene. The 260.0-kg spacecraft is attach
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Answer:

<em>The time interval required to lift the spacecraft to this specified height is 123.94 seconds</em>

Explanation:

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work done in this situation is proportional to the mechanical energy used to move the spacecraft up

work done = (weight of spacecraft) x (the height through which it is lifted)

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this means that

0.18 x 81619.2  = <em>14691.456 J  </em> is lost to friction.

Total useful mechanical energy =  81619.2 J - 14691.456 J = 66927.74<em> J</em>

Total power delivered by the crew to do this work = 135 x 4 = 540 W

But we know tat power is the rate at which work is done i.e

P = \frac{w}{t}

where p is the power

where w is the useful work done

t is the time taken to do this work

imputing values, we'll have

540 = 66927.74/t

t = 66927.74/540

time taken t = <em>123.94 seconds</em>

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