Answer:
The box contains 20 milk chocolates.
Step-by-step explanation:
Given that the chocolate box has milk chocolates and dark chocolates in a ratio of 2 milk chocolates for every 3 dark, and the total number of chocolates in the box is 50 units, to determine how many milk chocolates are in the box. it is necessary to perform the following calculation:
50 / (2 + 3)
50/5
10
Milk chocolates: 2 x 10 = 20
Dark chocolates: 3 x 10 = 30
Therefore, the box contains 20 milk chocolates.
You ca go to tiger math and put in any equation and it will give you the answer to any of them.
For this problem,we use the Fundamental Counting Principle. You know that there are 7 digits in a number. In this principle, you have to multiply the possible numbers for every digit. If the first number cannot be zero, then there are 9 possible numbers. So, the value for the first digit is 9. The second digit could be any number but less of 1 because it was used in the 1st digit. So, that would be 10 - 1 = 9. The third digit must be the value in the second digit less than 1. That would be 9 - 1 = 8. And so on and so forth. The solution would be:
9×9×8×7×6×5×4 = 544,320 7-digit numbers
For a cartesian equation

Given r = <span>10 tan(θ) sec(θ)

Therefore,</span>the curve is a parabola opening upward with vertex (0, 0).
Three hundred ten million, seven hundred sixty three thousand, one hundred thirty six