All categories

2 years ago

4. In the evenings, Jake and his friends would cook out and make smores for dessert. The ratio

Mathematics

1 answer:

lorasvet [3.4K]2 years ago

3 0

Answer:

A. y = 3/2x

B. you need 3 chocolate squares and 2 graham crackers to make 1 smore

C. 0, 0 chocolate squares and 0 graham crackers make 0 smores

Step-by-step explanation:

A. rise/run = 3/2

B. slope = 3/2

You might be interested in

Eggs were $2.05 per dozen on January 1st and $2.00 per dozen February 1st what percent did the price decrease during January?

Sholpan [36]

This is a 2.5% decrease in price.

8 0

3 years ago

Read 2 more answers

Find the GCF of the following literal terms. m^7 n^4 p^3 and mn^12 p^5

Dvinal [7]

$m^7n^4p^3=mn^4p^3\cdot m^6\\\\mn^{12}p^5=mn^4p^3\cdot n^8p^2\\\\GCF(m^7n^4p^3;\ mn^{12}p^5)=mn^4p^3$

6 0

2 years ago

Find the x-intercept and the y-intercept of 2x + 6y =24

viktelen [127]

Answer:

x-intercept = 12, y-intercept = 4

Step-by-step explanation:

To find the x and y intercept, substitute 0 in for both values.

Substitute 0 into x:

2(0) + 6y = 24

6y = 24

Divide each side by 6:

y = 4

Substitute 0 into y:

2x + 6(0) = 24

2x = 24

Divide each side by 2:

x = 12

4 0

2 years ago

In this population, suppose that immigration and emigration make the population size naturally variable between 2,000 and 14,000

alisha [4.7K]

Answer:

Step-by-step explanation:

i don't know i'm just kiding i know but i'm not giving you the answers

8 0

2 years ago

Let z denote a random variable that has a standard normal distribution. Determine each of the probabilities below. (Round all an

Gelneren [198K]

Answer:

(a) P (Z < 2.36) = 0.9909 (b) P (Z > 2.36) = 0.0091

(e) P (-0.77< Z > -0.55) = 0.0705 (f) P (Z > 3) = 0.0014

(g) P (Z > -3.28) = 0.9995 (h) P (Z < 4.98) = 0.9999.

Step-by-step explanation:

Let us consider a random variable, $X \sim N (\mu, \sigma^{2})$ , then $Z=\frac{X-\mu}{\sigma}$ , is a standard normal variate with mean, E (Z) = 0 and Var (Z) = 1. That is, $Z \sim N (0, 1)$ .

In statistics, a standardized score is the number of standard deviations an observation or data point is above the mean. The z-scores are standardized scores.

The distribution of these z-scores is known as the standard normal distribution.

(a)

Compute the value of P (Z < 2.36) as follows:

P (Z < 2.36) = 0.99086

≈ 0.9909

Thus, the value of P (Z < 2.36) is 0.9909.

(b)

Compute the value of P (Z > 2.36) as follows:

P (Z > 2.36) = 1 - P (Z < 2.36)

= 1 - 0.99086

= 0.00914

≈ 0.0091

Thus, the value of P (Z > 2.36) is 0.0091.

(c)

Compute the value of P (Z < -1.22) as follows:

P (Z < -1.22) = 0.11123

≈ 0.1112

Thus, the value of P (Z < -1.22) is 0.1112.

(d)

Compute the value of P (1.13 < Z > 3.35) as follows:

P (1.13 < Z > 3.35) = P (Z < 3.35) - P (Z < 1.13)

= 0.99960 - 0.87076

= 0.12884

≈ 0.1288

Thus, the value of P (1.13 < Z > 3.35) is 0.1288.

(e)

Compute the value of P (-0.77< Z > -0.55) as follows:

P (-0.77< Z > -0.55) = P (Z < -0.55) - P (Z < -0.77)

= 0.29116 - 0.22065

= 0.07051

≈ 0.0705

Thus, the value of P (-0.77< Z > -0.55) is 0.0705.

(f)

Compute the value of P (Z > 3) as follows:

P (Z > 3) = 1 - P (Z < 3)

= 1 - 0.99865

= 0.00135

≈ 0.0014

Thus, the value of P (Z > 3) is 0.0014.

(g)

Compute the value of P (Z > -3.28) as follows:

P (Z > -3.28) = P (Z < 3.28)

= 0.99948

≈ 0.9995

Thus, the value of P (Z > -3.28) is 0.9995.

(h)

Compute the value of P (Z < 4.98) as follows:

P (Z < 4.98) = 0.99999

≈ 0.9999

Thus, the value of P (Z < 4.98) is 0.9999.

**Use the z-table for the probabilities.

3 0

2 years ago