1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Rama09 [41]
3 years ago
14

Can someone please help me with this question?

Mathematics
2 answers:
gavmur [86]3 years ago
8 0
Ues. -2+-98/2=-51
-51< -64
lina2011 [118]3 years ago
4 0
No it is not a solutions because when you divide -98 by 2 you get -49 and add -2 to that it’s -51 which is more than -64
You might be interested in
Can someone help me with math
frozen [14]
-5.87 then -33 then 0.6 then 17
5 0
3 years ago
Read 2 more answers
Use the equation and type the ordered-palrs.<br> Y = 2^x
PSYCHO15rus [73]
What is the question
5 0
3 years ago
Consider randomly selecting a student at a large university, and let A be the event that the selected student has a Visa card an
ziro4ka [17]

Answer:

1) is not possible

2) P(A∪B) = 0.7

3) 1- P(A∪B) =0.3

4) a) C=A∩B' and P(C)= 0.3

b)  P(D)= 0.4

Step-by-step explanation:

1) since the intersection of 2 events cannot be bigger than the smaller event then is not possible that P(A∩B)=0.5 since P(B)=0.4  . Thus the maximum possible value of P(A∩B) is 0.4

2) denoting A= getting Visa card , B= getting MasterCard the probability of getting one of the types of cards is given by

P(A∪B)= P(A)+P(B) - P(A∩B) = 0.6+0.4-0.3 = 0.7

P(A∪B) = 0.7

3) the probability that a student has neither type of card is 1- P(A∪B) = 1-0.7 = 0.3

4) the event C that the selected student has a visa card but not a MasterCard is given by  C=A∩B'  , where B' is the complement of B. Then

P(C)= P(A∩B') = P(A) - P(A∩B) = 0.6 - 0.3 = 0.3

the probability for the event D=a student has exactly one of the cards is

P(D)= P(A∩B') + P(A'∩B) = P(A∪B) - P(A∩B) = 0.7 - 0.3 = 0.4

3 0
3 years ago
I put a random encouraging message on here just to spread some positivity/encouragement, and someone deleted it because it "went
malfutka [58]

Answer:

It was probably just because it wasnt a question.

Step-by-step explanation:

Hope this helps! Plz give brainliest!!

4 0
2 years ago
a card player selects a playing card from a well-shuffled deck of standard playing cards and sees if the card is a red card or n
DIA [1.3K]

It is not binomial random variable , since the number of red cards is unknown in the deck of cards in the starting of experiment.

As given in the question,

Number of cards are unknown.

Number of red cards are unknown in the starting of experiment.

Number of times process done =10

For binomial random variable number of red cards should be known.

Therefore, it is not binomial random variable , since the number of red cards is unknown in the deck of cards in the starting of experiment.

Learn more about binomial random variable here

brainly.com/question/14282621

#SPJ4

8 0
1 year ago
Other questions:
  • According to a recent report, customers who shop at a certain online store spend, on average, s1,500 a year at the store. To inv
    10·1 answer
  • Consider writing onto a computer disk and then sending it through a certifier that counts the number of missing pulses. Suppose
    11·1 answer
  • A teacher has $80 to buy workbooks. Each work book cost $3. If she buys as many workbooks as possible, how much money does she h
    9·1 answer
  • Please what is the answer?
    15·1 answer
  • How do u show 20720 in scientific notation
    8·1 answer
  • I need help asap !!!!!!!!
    7·2 answers
  • can anyone help me with this question? It’s the only one I don’t get. Any help would be much appreciated! Thanks!!
    6·1 answer
  • What are the answers to 1 2 and 3?
    10·1 answer
  • Please help if you want BRIANLEIST!!!
    8·1 answer
  • Please help will give brainliest
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!