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Paha777 [63]
3 years ago
13

The quotient of two numbers subtracted from 20

Mathematics
1 answer:
anastassius [24]3 years ago
5 0
The quotient of 2 unspecified numbers means division, being x/y - 20. hopefully this helped.
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Simplify x^2+3x-10/x^2-25
Natasha_Volkova [10]

Answer:

3x -10 / -25

Step-by-step explanation:

cancel off the x²

6 0
3 years ago
A function that models the profit for a new pet-monitoring system shows that there is no profit made until the price reaches $95
-Dominant- [34]

The profits at x = $185 is 0 and the graph is attached below:

<h3>What is graph?</h3>

Graph is a mathematical representation of a network and it describes the relationship between lines and points.

Function is to model the profits of a new pet-monitoring system, so, if the profits are y and x then y = f(x)

The curve shows that y is negative at values of x< $95, then the profits increase when x varies between $95 and $140.

The profits reach a maximum at $140 and then the profits start to reduce as x increases again.

So, the profits at x = $185 is 0.

Learn more about this concept here:

brainly.com/question/16887458

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6 0
1 year ago
A= 2LW+2LH+2HW solve w
svetlana [45]
Pkay so here is YOUR ansew=wer uyour welcoeme i am ammath lover it is cofrrect W=(2LH/2L+2H)A
6 0
3 years ago
Suppose that an airline uses a seat width of 16.5 in. Assume men have hip breadths that are normally distributed with a mean of
Alexxx [7]

Answer:

a) 0.018

b) 0            

Step-by-step explanation:

We are given the following information in the question:

Mean, μ =  14.4 in

Standard Deviation, σ = 1 in

We are given that the distribution of breadths is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

a) P(breadth will be greater than 16.5 in)

P(x > 16.5)

P( x > 16.5) = P( z > \displaystyle\frac{16.5 - 14.4}{1}) = P(z > 2.1)

= 1 - P(z \leq 2.1)

Calculation the value from standard normal z table, we have,  

P(x > 16.5) = 1 - 0.982 = 0.018 = 1.8\%

0.018 is the probability that if an individual man is randomly​ selected, his hip breadth will be greater than 16.5 in.

b) P( with 123 randomly selected​ men, these men have a mean hip breadth greater than 16.5 in)

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}  

P(x > 16.5)  

P( x > 16.5) = P( z > \displaystyle\frac{16.5-14.4}{\frac{1}{\sqrt{123}}}) = P(z > 23.29)  

= 1 - P(z \leq 23.29)

Calculation the value from standard normal z table, we have,  

P(x > 16.5) = 1 - 1 = 0

There is 0 probability that 123 randomly selected men have a mean hip breadth greater than 16.5 in

4 0
3 years ago
A type of new car loses 20% of its value in its first year.
coldgirl [10]

Answer:63%

Step-by-step explanation:

if 2years=25%loss

Then 5years=5/2×25%

=62.5%~63%

3 0
3 years ago
Read 2 more answers
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