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3 years ago

PLEASE HELP!!! will mark brainliest

Mathematics

1 answer:

nexus9112 [7]3 years ago

3 0

C the answer is c the median of the data will always be the line within the box

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Can someone pls help me fast

Bezzdna [24]

The slope is 1

Hope I didn't mess up for your sake

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3 years ago

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(2b/3)^4 simplify the expression

Vladimir [108]

Answer:

$\large\boxed{\left(\dfrac{2b}{3}\right)^4=\dfrac{16b^4}{81}}$

Step-by-step explanation:

$\left(\dfrac{2b}{3}\right)^4\qquad\text{use}\ \left(\dfrac{a}{b}\right)^n=\dfrac{a^n}{b^n}\ \text{and}\ (ab)^n=a^nb^n\\\\=\dfrac{2^4b^4}{3^4}=\dfrac{16b^4}{81}$

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3 years ago

(-8, 4), (4, -4)<br> Write in standard form

Serjik [45]

Answer written in standard form:

2x + 3y = -4

7 0

2 years ago

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Question 1<br> What is the dashed part of the figure below?

Afina-wow [57]

Where is the figure at?

8 0

3 years ago

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This parabola has<br> x-intercepts

slega [8]

Answer:

see the explanation

Step-by-step explanation:

we have the quadratic equation

$y=-16x^{2} +32x-10$

This is a vertical parabola open downward

The vertex is a maximum

Find the x-intercepts of the quadratic equation

The x-intercepts are the values of x when the value of y is equal to zero

For y=0

$-16x^{2} +32x-10=0$

Solve the quadratic equation

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$-16x^{2} +32x-10=0$

$a=-16\\b=32\\c=-10$

substitute in the formula

$x=\frac{-32(+/-)\sqrt{32^{2}-4(-16)(-10)}} {2(-16)}$

$x=\frac{-32(+/-)\sqrt{384}} {-32}$

$x=\frac{-32(+/-)8\sqrt{6}}{-32}$

$x=\frac{-32(+)8\sqrt{6}}{-32}=\frac{32(-)8\sqrt{6}}{32}=0.39\ sec$

$x=\frac{-32(-)8\sqrt{6}}{-32}=\frac{32(+)8\sqrt{6}}{32}=1.61\ sec$

therefore

This parabola has two x-intercepts representing the times when the dolphin's height above water is zero feet

8 0

2 years ago

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