An object is 20cm in front of convex mirror if the image height is 1/5 times the object height determine 1. The image distance 2
. The focal length 3. The properties of image
1 answer:
Explanation:
It is given that,
Focal length
f=−20cm
hi=3ho
The image is three times the size of the object. So there are two cases.
Case 1. For real image
m=−uv=−3
v=3u
Using mirror’s formula
f1=v1+u1
−201=3u1+u1
u=3−80cm
Case 2. For virtual image
m=u−v=+3
v=−3u
Again using mirror’s formula
−201=−3u1+u1
u=3−40cm
The possible values of u are 3−80cmand3−40cm.
You might be interested in
It shows that the airplane covers equal distance in equal time interval, that's it has a straight line from the origin.
The plane is moving at uniform speed.
What counteracts gravity is buoyancy.
As per kinematics equation we are given that
now we are given that
a = 2.55 m/s^2
now we need to find x
from above equation we have
so it will cover a distance of 93.2 m
the temperature
increases
Will this one work?...................
