Question

Imagine you derive the following expression by analyzing the physics of a particular system: v2=v20+2ax. The problem requires solving for x, and the known values for the system are a=2.55meter/second2, v0=21.8meter/second, and v=0meter/second. Perform the next step in the analysis.

Answer 1

As per kinematics equation we are given that

$v^2 = v_o^2 + 2ax$

now we are given that

a = 2.55 m/s^2

$v_0 = 21.8 m/s$

$v = 0$

now we need to find x

from above equation we have

$0^2 = 21.8^2 + 2(2.55)x$

$0 = 475.24 + 5.1 x$

$x = 93.2 m$

so it will cover a distance of 93.2 m

Answer 2

Answer:

x = -93.18 meters

Explanation:

The equation is given as :

$v^2=v_o^2+2ax$...........(1)

The known values are as follows:

$a=2.55\ m/s^2$

$v_o=21.8\ m/s$

$v=0\ m/s$

Putting all the values in equation (1) as :

$0=(21.8\ m/s)^2+2\times 2.55\ m/s^2\times x$

x = -93.18 meters

So, the vale of x is 93.18 meters. Hence, this is the required solution.