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SCORPION-xisa [38]
3 years ago
9

4. Suppose the observed motion of a moving airplane, illustrated by a distance vs. time graph, is nearly a straight line with ze

ro distance traveled at zero time. State what this shows about the relationship between distance and time, name the type of relationship, and tell what it indicates about the speed of the airplane.
Physics
1 answer:
jekas [21]3 years ago
7 0
It shows that the airplane covers equal distance in equal time interval, that's it has a straight line from the origin.

The plane is moving at uniform speed.
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The dimensions of a room are 16.40 m long, 4.5 m wide and 3.26 m high. What is the volume of the room in cubic meters? Express y
gtnhenbr [62]

Answer:

V=2.4\times 10^2\ \text{m}^3

Explanation:

Given that,

The dimensions of a room are 16.40 m long, 4.5 m wide and 3.26 m high.

We need to find the volume of the room.

The room in the shape of cuboid whose volume is given by :

V=L\times B\times H

L,B,H are length, breadth and height of the room

So,

V=16.4\times 4.5\times 3.26\\\\V=240.588\ \text{m}^3\\\\\text{In scientific notation}\\\\V=2.4\times 10^2\ \text{m}^3

Hence, the volume of the room is 2.4\times 10^2\ \text{m}^3

5 0
3 years ago
Which of the following best explains how the Ptolemy’s (geocentric) and Copernicus’s (heliocentric) models of the solar system d
TiliK225 [7]

Answer:

The correct answer is c

Explanation:

In these two different models of movement of the planets

Ptolemy raises the Earth as the center of the solar system

In the Copernicus system, it poses the Sun as the center of the solar system.

Copernicu's system was accepted for giving a simpler and more complete explanation of the problem

The correct answer is c

7 0
4 years ago
Vector B has x, y, and z components 4, 6, and 3, respectively.
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8 0
3 years ago
A current of 0.96 amps flows through a copper wire 0.44 mm in diameter when connected to a potential difference of 15 v. how lon
FinnZ [79.3K]
By using Ohm's law, we can calculate the resistance of the wire. Ohm's law states that:
V=IR
where V is the potential difference across the conductor, I is the current and R the resistance. Rearranging the equation, we get
R= \frac{V}{I}= \frac{15 V}{0.96 A}=15.6 \Omega

Now we can use the following equation to calculate the length of the wire:
R= \frac{\rho L}{A} (1)
where
\rho is the resistivity of the material
L is the length of the conductor
A is its cross-sectional area
In this problem, we have a wire of copper, with resistivity \rho=1.68 \cdot 10^{-8} \Omega m. The radius of the wire is half the diameter:
r= \frac{d}{2}= \frac{0.44 mm}{2}=0.22 mm=0.22 \cdot 10^{-3} m
And the cross-sectional area is
A=\pi r^2=\pi (0.22 \cdot 10^{-3}m)^2=1.52 \cdot 10^{-7} m^2

So now we can rearrange eq.(1) to calculate the length of the wire:
L= \frac{RA}{\rho}= \frac{(15.6 \Omega)(1.52 \cdot 10^{-7} m^2)}{1.68 \cdot 10^{-8} \Omega m}=141.1 m
8 0
3 years ago
Francium decays with a half-life of 22 minutes. If we start out with 639 mg of francium,how much would remain after 2.7 hours?
Vinil7 [7]

Answer:

3.87 or 3.9 mg

Explanation:

2.7h * 60mins = 162mins

number of 1/2 lives = 162/22= 7.364

amount remaining = 639(1/2)^7.364 = 3.8796

answer = 3.87 or 3.9

6 0
3 years ago
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