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3 years ago

Is the direction of current through a battery always from the negative terminal to the positive one?

Physics

2 answers:

rodikova [14]3 years ago

8 0

Answer:

Yes. The current is actually flow of charge and in actual situation electrons flow from negative terminal to positive terminal. But in physics the convention of positive charge flow is used i.e. we take the direction of current from positive to negative terminal.

Explanation:

diamong [38]3 years ago

3 0

Poorly written question.

The direction of current through a CIRCUIT is always from the negative terminal of the battery to the positive one.

But the battery develops it's voltage and supplies its current and energy by chemical processes going on everywhere inside the battery, so it's not applicable to talk about any particular current "through" a battery.

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A circular loop of wire with a radius of 20 cm lies in the xy plane and carries a current of 2 A, counterclockwise when viewed f

Zina [86]

To solve this problem we will apply the concept related to the magnetic dipole moment that is defined as the product between the current and the object area. In our case we have the radius so we will get the area, which would be

$A=\pi r^2$

$A =\pi (0.2)^2$

$A =0.1256 m^2$

Once the area is obtained, it is possible to calculate the magnetic dipole moment considering the previously given definition:

$\mu=IA$

$\mu=2(0.1256)$

$\mu=0.25 A\cdot m^2$

Therefore the magnetic dipole moment is $0.25A\cdot m^2$

6 0

3 years ago

A single conducting loop of wire has an area of 7.26E-2 m2 and a resistance of 117 Ω. Perpendicular to the plane of the loop is

cricket20 [7]

Answer:

$\frac{dB}{dt}$ = 591.45 T/s

Explanation:

i = induced current in the loop = 0.367 A

R = Resistance of the loop = 117 Ω

E = Induced voltage

Induced voltage is given as

E = i R

E = (0.367) (117)

E = 42.939 volts

$\frac{dB}{dt}$ = rate of change of magnetic field

A = area of loop = 7.26 x 10⁻² m²

Induced emf is given as

$E = A\frac{dB}{dt}$

$42.939 = (7.26\times 10^{-2})\frac{dB}{dt}$

$\frac{dB}{dt}$ = 591.45 T/s

3 0

3 years ago

Keisha analyzes this circuit diagram.

Mazyrski [523]

Component ' W ' is the standard schematic symbol for a switch.

The short line between the two circles can be shown straight,
like it is now, when the switch is 'closed' and current can flow.

Or, it can also be drawn slightly tilted, so it's not touching one
of the circles. In that case, the switch is 'open', no current can
flow through it, and the whole circuit is shut down.

9 0

3 years ago

Read 2 more answers

By applying a force of one Newton, one can hold a body of mass _

SVEN [57.7K]

Answer:

By applying a force of one Newton, one can hold a body of mass of 102 gram.

Explanation:

Force is the pull or push of an object. It can be mathematically measured as, F= m* g.

where, F= force in newton

m= mass in kg

g= acceleration due to gravity ( $meter/second^{2}$ )

For 1 newton force,

F= m* 9.8

or, m= $\frac{1}{9.8}$ = 0.102 kg

or, m= 102 gram.

Hence, 102 gram mass can be hold by one Newton force.

3 0

3 years ago

Which of the following equations represents the law of universal gravitation

Xelga [282]

<span>Newton's law of universal gravitation is an INVERSE SQUARE LAW, which rules out C and D.It is proportional to the masses involved, which rules out B.A could be seen as one form of the lawF=G m1 m1/r^2Though I recognise it more as F=G m1 m2/r^2.G is the universal gravity constant and is distinct from g which is the acceleration of gravity LOCAL to a planet or moon. So, g is LOCAL, G is universal.Newton was a smart bloke, as are all these scientists whose names frequently appear.
</span>

8 0

3 years ago