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jeka94
3 years ago
12

By applying a force of one Newton, one can hold a body of mass _​

Physics
1 answer:
SVEN [57.7K]3 years ago
3 0

Answer:

By applying a force of one Newton, one can hold a body of mass of 102 gram.

Explanation:

  • Force is the pull or push of an object. It can be mathematically measured as, F= m* g.

                       where, F= force in newton

                                  m= mass in kg

                                  g= acceleration due to gravity (meter/second^{2} )

  • For 1 newton force,

                                   F= m* 9.8

                            or,   m= \frac{1}{9.8}= 0.102 kg

                            or,   m= 102 gram.

  • Hence, 102 gram mass can be hold by one Newton force.

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Consider a thin circular disk that has been heated up to 400 °C and then left inside a chamber to cool down. The chamber surface
kogti [31]

Answer:

hello your question lacks the required diagram attached below is the complete question with the required diagram

answer : Qtotal = 807.4 Mw

Explanation:

Given Data :

disk properties :

∈ = 0.65

D = 200 mm

Ts = 400⁰c

attached below is the detailed solution

The total rate of Heat transferred from the disk

Qtotal = 807.4 Mw

7 0
3 years ago
Use your understanding of heat loss to ESTIMATE the cost of the lost energy through one standard window during an average summer
miskamm [114]

Answer:

The cost of energy is $ 0.34.

Explanation:

The energy is the capacity to do work.

The energy is a scalar quantity and its SI unit is Joule.

The commercial unit of energy is kWh.

Cost of 1 kWh energy = $ 0.17

energy loss by standard window is 2 kWh .

So, the cost of lost of energy is

Cost = $ 0.17 x 2 = $ 0.34

3 0
3 years ago
Determine the acceleration of a pendulum bob as it passes through an angle of 15 degrees to the right of the equilibrium point.
BigorU [14]

Answer:

Explanation:

Since energy is conserved:

2

mu  

2

 

​

=  

2

mv  

2

 

​

+mgh

⇒u  

2

=v  

2

+2gh

⇒(3)  

2

=v  

2

+2(9.8)(0.5−0.5cos60)

⇒v=2m/s

7 0
3 years ago
Which of the following is NOT a benefit of cool down activities?
quester [9]
B. Maximal lightheadedness
5 0
3 years ago
Read 2 more answers
An electric field of intensity 3.7 kN/C is applied along the x-axis. Calculate the electric flux through a rectangular plane 0.3
jekas [21]

Answer:

a)906.5 Nm^2/C

b) 0

c) 742.56132 N•m^2/C

Explanation:

a) The plane is parallel to the yz-plane.

We know that

flux ∅= EAcosθ

3.7×1000×0.350×0.700=906.5 N•m^2/C

(b) The plane is parallel to the xy-plane.

here theta = 90 degree

therefore,

0  N•m^2/C

(c) The plane contains the y-axis, and its normal makes an angle of 35.0° with the x-axis.

therefore, applying the flux formula we get

3.7×1000×0.3500×0.700×cos35°= 742.56132 N•m^2/C

4 0
3 years ago
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