Answer:
1s2,2s2,2p6 or (He) 2s2 2p6
This is the open switch 2 cells connecting wire and bulb
Only 10 Kg of secondary consumers can be supported by the ecosystem.
There exists such a thing as the 10% rule in the transfer of energy in biomass from one trophic level to another. This rule ultimately controls the mass of biomass that is available at the next higher trophic level.
This rule state that only 10% of the energy in biomass is transferred to the next trophic level. By this rule, only 10% of the energy in the plant material is transferred to the carnivore population. Therefore, only 10 Kg of secondary consumers can be supported by the ecosystem.
Learn more about trophic level: brainly.com/question/13267087
<em>The question is incomplete and doesn't have any requirement. I'm computing the angle at which the dart should have been thrown to hit in the center of the target</em>
Answer:
The dart should be thown with an angle of elevation of
Explanation:
<u>Horizontal and Diagonal Motion</u>
When an object is launched horizontally, its initial vertical speed is zero and the horizontal component remains the same in time. If the initial velocity forms an angle with the horizontal, then the vertical velocity has an initial value which can be positive or negative depending on the angle (above or below the horizontal).
The dart is thrown horizontally and when it reaches the target, 5 meters away, the center of the target was missed by 0.15 meters below. The question doesn't have any requirement, but I'll assume you want to know at what angle should the dart be thrown at the same speed, to be exact on target.
Let's start with the original horizontal launching. The distance x is computed as
The distance y is
We need to find the value of , given x and y. Solving for t in the last equation
Replacing in x
Solving for
Now, let's suppose we try to reach the center of the target by throwing the dart at the same speed but with a certain angle above the horizontal. That way, the formulas for x changes to
Replacing the value of
Operating
Simplifying
Solving for the angle
Answer:
<em>d. The sail should be reflective because in this case the momentum transferred to the sail per unit area per unit time is larger than for absorbing sail, therefore the radiation pressure is larger for the reflective sail.</em>
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Explanation:
Let us take the momentum of a photon unit as u
we know that the rate of change of momentum is proportional to the force exerted.
For a absorbing surface, the photon is absorbed, therefore the final momentum is zero. From this we can say that
F = (u - 0)/t = u/t
for a unit time, the force is proportional to the momentum of the wave due to its energy density. Therefore,
F = u
For a reflecting surface, the momentum of the wave strikes the sail and changes direction. Since we know that the speed of light does not change, then the force is proportional to
F = (u - (-u))/t = 2u/t
just as the we did above, it becomes
F = 2u.
From this we can see that the force for a reflective sail is twice of that for an absorbing sail, and we know that the pressure is proportional to the force for a given area. From these, we conclude that <em>the sail should be reflective because in this case the momentum transferred to the sail per unit area per unit time is larger than for absorbing sail, therefore the radiation pressure is larger for the reflective sail.</em>
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