Explanation:
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Answer:
Speed is same as that before it entered glass.
Explanation:
Given:
A light ray enters and passes through the glass as shown in the diagram.
We have to analyze its speed.
Speed of light in air is and speed of light in glass is
Whenever a light ray enters a glass block or slab there is bending of light at the interface of the two media.
So speed of light will decrease in glass medium and again it passes to the air.
So
Speed of light in air will again increase or will be equivalent to the earlier speed when it was entering the glass block.
Finally
Speed is same as that before it entered glass as it in the same medium (air).
Answer:
0.36 A.
Explanation:
We'll begin by calculating the equivalent resistance between 35 Ω and 20 Ω resistor. This is illustrated below:
Resistor 1 (R₁) = 35 Ω
Resistor 2 (R₂) = 20 Ω
Equivalent Resistance (Rₑq) =?
Since, the two resistors are in parallel connections, their equivalence can be obtained as follow:
Rₑq = (R₁ × R₂) / (R₁ + R₂)
Rₑq = (35 × 20) / (35 + 20)
Rₑq = 700 / 55
Rₑq = 12.73 Ω
Next, we shall determine the total resistance in the circuit. This can be obtained as follow:
Equivalent resistance between 35 Ω and 20 Ω (Rₑq) = 12.73 Ω
Resistor 3 (R₃) = 15 Ω
Total resistance (R) in the circuit =?
R = Rₑq + R₃ (they are in series connection)
R = 12.73 + 15
R = 27.73 Ω
Finally, we shall determine the current. This can be obtained as follow:
Total resistance (R) = 27.73 Ω
Voltage (V) = 10 V
Current (I) =?
V = IR
10 = I × 27.73
Divide both side by 27.73
I = 10 / 27.73
I = 0.36 A
Therefore, the current is 0.36 A.
Answer:
1.56 × 10^-3 cm.
Explanation:
So, we are given the following parameters from the question above;
Length = 3.67 cm, breadth = 2.93 cm, and the number of embedded transistors = 3.5 million.
Step one: find the area of the computer chip.
Therefore, Area = Length × breadth.
Area = 3.67 cm × 2.93 cm.
Area of the computer chip = 10.7531 cm^2. = 10.75 cm^2.
Step two: find the area of one transistor
The area of one transistor is; (area of the computer chip) ÷ (number of embedded transistors).
Hence;
The area of one transistor= 10.7531/4.4 × 10^6.
The area of one transistor= 2.44 × 10^-6 cm^2.
=> Note that We have our transistors as square, therefore;
The maximum dimension = √ (2.44 × 10^-6) cm^2.
The maximum dimension= 1.56 × 10^-3 cm.
Answer:
it is sublimation because There are three ways heat is transferred into and through the atmosphere:
radiation.
conduction.
convection.
Explanation:
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