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shutvik [7]
3 years ago
9

Which equations could be used as is, or rearranged to calculate for frequency of a wave? Check all that apply.

Physics
2 answers:
amm18123 years ago
7 0
-- Equations  #2  and  #6  are both the same equation,
and are both correct.

-- If you divide each side by  'wavelength', you get Equation #4,
which is also correct.

-- If you divide each side by  'frequency', you get Equation #3,
which is also correct. 
With some work, you can rearrange this one and use it to calculate
frequency.

Summary:

-- Equations #2, #3, #4, and #6 are all correct statements,
and can be used to find frequency.

-- Equations #1 and #5 are incorrect statements.
alexira [117]3 years ago
3 0

The correct answers to the question are 2,3,4 and 6 options respectively.

EXPLANATION:

Let us consider a wave which is moving with a speed v in a medium .

Let f and \lambda is the frequency and wavelength of the wave.

The relation between frequency,wavelength and speed is given as -

                       speed = =\ frequency\times wavelength

                                   = f\times \lambda

The wavelength of the wave is calculated as -

                             wavelength=\ \frac{speed}{frequency}

Similarly frequency of the wave can be calculated as-

                            frequency=\ \frac{speed}{wavelength}

The option 1 is a wrong relation. So, we can not calculate the wavelength through this equation.

The option 2 is a right relation. By rearranging it, we can calculate the frequency of the wave.

The option 3 is a correct relation. So, we can calculate the wavelength through it.

The option 4 is also a correct relation. By rearranging it, we can calculate the wavelength.

The option 5 is a wrong relation.

The option 6 is also a right relation. By rearranging it, we can calculate the wavelength of the wave.

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Answer:

The speed of the ambulance is 4.30 m/s

Explanation:

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Speed of the cyclist, v₀ = 2.36 m/s

let the velocity of the ambulance be 'vₓ'

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the Doppler effect is given as:

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since the ambulance is moving towards the cyclist. thus, the sign will be positive

thus,

v_x=\frac{f}{f'}(v+v_o)-v

on substituting the values, we get

v_x=\frac{1790}{1780}(343+2.36)-343

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A ship maneuvers to within 2.46×10³ m of an island’s 1.80 × 10³ m high mountain peak and fires a projectile at an enemy ship 6.1
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Answer:

The distance close to the peak is 597.4 m.

Explanation:

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Distance of the first ship from the mountain d=2.46\times10^{3}\ m

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Distance of the enemy ship from the mountain d'=6.10\times10^{2}\ m

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We need to calculate the horizontal component of initial velocity

Using formula of horizontal component

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We need to calculate the vertical component of initial velocity

Using formula of vertical component

v_{y}=v\sin\theta

Put the value into the formula

v_{y}=2.55\times10^{2}\sin74.9

v_{y}=246.19\ m/s

We need to calculate the time

Using formula of time

t=\dfrac{d}{v_{x}}

t=\dfrac{2.46\times10^{3}}{66.42}

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We need to calculate the height of the shell on reaching the mountain

Using equation of motion

H= v_{y}t-\dfrac{1}{2}gt^2

Put the value in the equation

H=246.19\times37.03-\dfrac{1}{2}\times9.8\times(37.03)^2

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Using formula of distance

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Put the value into the formula

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