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3 years ago

A negative test charge experiences a force to the right as a result of an electric field. Which is the best conclusion to

Physics

1 answer:

meriva3 years ago

8 0

$\mathfrak{\huge{\pink{\underline{\underline{AnSwEr:-}}}}}$

Actually Welcome to the Concept of the Electrostatics.

Basically here we can see that, the Negative test charge usually a Electron is facing a force from the right side, this we can say that a Electric field as like charge is creating a repulsive force from the right to left side.

thus,

1) The electric field points to the left because the force on a negative charge is opposite to the direction of the field.

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With a thunderstorm brewing, an electric field of magnitude 2.0 × 102 newtons/coulomb exists at a certain point in the earth’s a

hichkok12 [17]

(2.0 x 10² N/Coul) x (-1.6 x 10⁻¹⁹ Coul) = -3.2 x 10⁻¹⁷ N

The magnitude is 3.2 x 10⁻¹⁷ Newton.

3 0

4 years ago

En un m.A.S. La amplitud tiene un valor de 10 centimetros y el periodo es de 2 segundos calcular el valor de la velocidad de 0.8

Ivanshal [37]

Answer:

v1=18.46m/s

v2=29.8cm/s

Explanation:

We know that

$A=10cm\\T=2s$

the equation of the motion is

$x=Acos(\omega t)\\$

we can calculate w by using

$\omega=\frac{2\pi}{T}=\frac{2\pi}{2}=\pi$

Hence, we have that

$x=10cm*cos(\pi t)\\$

the speed will be

$v=-\omega*Asin(\omega t)\\|v(0.8)|=|\pi*10cm*sin(\pi *0.8)|=18.46\frac{cm}{s}\\|v(1.4)|=|\pi*10cm*sin(\pi *1.4)|=29.8\frac{cm}{s}$

hope this helps!

6 0

3 years ago

A particle moves so that its position as a function of time in SI units is r = i + (3.0) t2 j + t k. Write expressions for its v

maksim [4K]

Answer:

i - component of V is zero for any value of t i-e no motion in this direction

Explanation:

Since

r= i+3 $t^{2}$ j+t k

==> V = $\frac{d r}{dt}$ = $\frac{d(i+3t^{2}j+kt) }{dt}$

= $6tj+k$

and acceleration is given by taking derivative of velocity w.r.t t

==> a= $\frac{dV}{dt}$ = $\frac{d(6tj+k)}{dt}$ = $6j$

so, V=0i+6tj+k

and

a = 0i+6j+k

i - component of V is zero for any value of t i-e no motion in this direction

6 0

3 years ago

In a transformer a 120 volt dc Primary of 500 turns is connected to a secondary of 75 turns. What is the Induced voltage in the

oee [108]

Answer:

The induced voltage in the Secondary is 18 volt.

Explanation:

Given that,

Voltage = 120 volt

Number of turns in primary = 500

Number of turns in secondary = 75

We need to calculate the induced voltage in the Secondary

Using relation number of turns and voltage in primary and secondary

$\dfrac{V_{p}}{V_{s}}=\dfrac{N_{p}}{N_{s}}$

Where, $N_{p}$ = Number of primary coil

$N_{s}$ = Number of secondary coil

$V_{p}$ = Voltage of primary coil

Put the value into the formula

$\dfrac{120}{V_{s}}=\dfrac{500}{75}$

$V_{s}=\dfrac{120\times75}{500}$

$V_{s}=18\ Volt$

Hence, The induced voltage in the Secondary is 18 volt.

7 0

3 years ago

As a snowboarder descends a mountain slope, gravity, the normal force, and friction combine to exert a net force of 320 N in the

Elis [28]

Answer:

34.75m

Explanation:

Parameters given:

Net force, F = 320N

Work done by net force, W = 4700 N

Angle, θ = 65º

Work done at an angle is given as:

W = F * d * cosθ

Where d = distance travelled

θ is the angle between the force and the direction of motion.

Therefore,

4700 = 320 * d * cos65

=> d = 4700/(320 * cos65)

d = 34.75 m

3 0

4 years ago